Question

table1＆amp;表2：

table1 & table2 http://aftabfarda.parsfile.com/1.png

SELECT     *
FROM         (SELECT DISTINCT dbo.tb1.ID, dbo.tb1.name, ROW_NUMBER() OVER (ORDER BY tb1.id DESC) AS row
FROM         dbo.tb1 INNER JOIN
                      dbo.tb2 ON dbo.tb1.ID = dbo.tb2.id_tb1) AS a
WHERE     row BETWEEN 1 AND 7
ORDER BY id DESC

结果：

Result... http://aftabfarda.parsfile.com/3.png

（id 11重复3次）

我如何获得此输出：

ID  name    row
--  ------  ---
11  user11  1
10  user10  2
9   user9   3
8   user8   4
7   user7   5
6   user6   6
5   user5   7

Answer 1

您可以使用子查询在distinct之前应用row_number：

select  *
from    (
        select  row_number() over (order by tbl.id desc) as row
        ,       *
        from    (
                select  distinct t1.ID
                ,       tb1.name
                from    dbo.tb1 as t1
                join    dbo.tb2 as t2
                on      t1.ID = t2.id_tb1
                ) as sub_dist
        ) as sub_with_rn
where   row between 1 and 7

Answer 2

除@Andomar's suggestion之外，您可以使用DENSE_RANK代替ROW_NUMBER并先排序（在子查询中），然后应用{{1} （在外部查询中）：

DISTINCT

类似但不完全相同，虽然两者可能归结为相同的查询计划，但我不确定。我认为值得测试。

当然，你也可以尝试半 -join而不是SELECT DISTINCT ID, name, row FROM ( SELECT t1.ID, t1.name, DENSE_RANK() OVER (ORDER BY t1.ID DESC) AS row FROM dbo.tb1 t1 INNER JOIN dbo.tb2 t2 ON t1.ID = t2.id_tb1 ) AS a WHERE row BETWEEN 1 AND 7 ORDER BY ID DESC或IN形式的正确联接，以防止重复第一名：

EXISTS

如何删除分页中的重复项

2 个答案: