Question

在php中获取相关内容有什么好方法。我有$关键字，如果我在其中使用标题LIKE'％$ keyword％'它返回same.my方法很简单：

$keywords = 'Most Perfectly Timed Videos EVER';
$rel = mysql_query("select * from media where title LIKE '%$keywords%'")or
die(mysql_error());

我希望最大结果与我的关键字相关。感谢。

Answer 1

$query = "SELECT * FROM media WHERE ";
$keywords = 'Most Perfectly Timed Videos EVER';
$keywords = explode(" ", $keywords);
$where = "";
foreach($keywords as $k => $v)
{
    $where .= "title LIKE '%".$v."%' AND ";
}
$where = substr($where, 0, -5); //deleting the last "AND"

$query .= $where;
$rel = mysql_query($query) or die(mysql_error());

或者，如果你想使用“OR”而不是“AND”来获得更好的结果：

foreach($keywords as $k => $v)
{
    $where .= "title LIKE '%".$v."%' OR ";
}
$where = substr($where, 0, -4);

什么是获取相关内容的好方法

1 个答案: