我有两张桌子：
CREATE TABLE "LOCATION" (
"ID" NUMBER(19,0) NOT NULL ENABLE,
"VERSION" NUMBER(19,0) NOT NULL ENABLE,
"DELETEULD" NUMBER(1,0) DEFAULT 0 NOT NULL ENABLE,
"INBOUND" NUMBER(1,0) DEFAULT 0 NOT NULL ENABLE,
"AAENABLED" NUMBER(1,0) DEFAULT 0 NOT NULL ENABLE,
"WSUPLDTOOL" NUMBER(1,0) DEFAULT 0 NOT NULL ENABLE,
"CISDEST" VARCHAR2(7 CHAR),
"REVRECOVERY" NUMBER(1,0) DEFAULT 0,
CONSTRAINT "LOCATION_ID" PRIMARY KEY ("ID") ENABLE )
CREATE TABLE "TSLD164"."FTP_SCAN_EVENTS"
(
"HOSTNAME" VARCHAR2(200 BYTE),
"DIRECTORY" VARCHAR2(200 BYTE),
"USERNAME" VARCHAR2(20 BYTE),
"PASSWORD" VARCHAR2(20 BYTE),
"LOCATION_ID" NUMBER(19,0) NOT NULL ENABLE,
CONSTRAINT "FTP_SCAN_EVENTS_LOCATION_FK1" FOREIGN KEY ("LOCATION_ID") REFERENCES "LOCATION" ("ID") ENABLE
)
与FK和PK相关的表（Location_Id列和Id）
我有一个表单，其中包含以上所有列作为字段。但是，表FTP_SCAN_EVENTS中的列是隐藏的，并且通过选择它们显示在表单中的复选框(REVRECOVERY)。用户可以动态添加行如果他想要的话。
<td><form:checkbox path="revRecovery" onclick="showMe('div1',this), showMe('i1',this)"/>
<input type="hidden" value="1" name="_revRecovery"/>
FTP Scan Events</td></tr><tr><td colspan="4">
<table id="div1" style="display:none">
<tr><td><input type="text" value="hostname" onfocus="if(this.value == 'hostname'){this.value =''}" onblur="if(this.value == ''){this.value ='hostname'}" size="30" maxlength="200"/></td>
<td><input type="text" value="directory" onfocus="if(this.value == 'directory'){this.value =''}" onblur="if(this.value == ''){this.value ='directory'}" size="30" maxlength="200"/></td>
<td><input type="text" value="username" onfocus="if(this.value == 'username'){this.value =''}" onblur="if(this.value == ''){this.value ='username'}" size="20" maxlength="20"/></td>
<td><input type="text" value="password" onfocus="if(this.value == 'password'){this.value =''}" onblur="if(this.value == ''){this.value ='password'}" size="20" maxlength="20"/></td></tr>
</table>
</td></tr>
<tr id="i1" style="display:none"><td><input type="button" onclick="addRow()" value="+"/>
<input type="button" onclick="removeRowFromTable();" value="-" />
</td></tr>
我的位置hbm文件：
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="ca.ups.tundra.model">
<class name="Location" table="LOCATION">
<id name="id" access="field" type="long">
<generator class="native"/>
</id>
<version name="version" access="field" column="VERSION" type="long"/>
<property name="cisDest" type="string" column="CISDEST" length="7" not-null="true"/>
<property name="revRecovery" type="boolean" not-null="true"/>
<property name="deleteUld" type="boolean" not-null="true"/>
<property name="inbound" type="boolean" not-null="true"/>
<property name="aaEnabled" type="boolean" not-null="true"/>
<property name="wsUpldTool" type="boolean" not-null="true"/>
<property name="locationType" type="string" column="LOCATIONTYPE" length="2" not-null="true"/>
<set name="groups" table="LOCATIONGROUPS" cascade="save-update" access="field">
<key column="LOCATION_ID"/>
<many-to-many class="LocationGroup" column="GROUP_ID"/>
</set>
</class>
</hibernate-mapping>
Location的模型类只是setter和getter方法。
我需要将我的第二个表映射到与上面相同的映射文件中，并且需要为getter和setter方法使用相同的模型类。
答案 0 :(得分：0)
根据您的说明，您需要查看<join/>。但是，由于您没有具体说明，我只能一般地帮助您。基本上<join/>（与JPA @SecondaryTable相同的功能）允许您将两个表之间的连接列视为一个组合行，以定义实体的基本类型。有一些注意事项，比如期待“共享主键”（又名真正的一对一）集;有关详细信息，请参阅文档。无论如何，假设您有一个名为location_supp的辅助表，其中名为location_id的PK引用（FK）到Location.LocationId，您会说：
<class name="Location" table="Location" ...>
<id name="id" column="LocationId" .../>
<property name="name" column="name" .../>
<!-- mappings for other columns from Location table -->
<join table="location_supp">
<!--
key defines the pk column of that joined table which is assumed to
also be the foreign-key source column referring back to Location
-->
<key column="location_id"/>
<!-- mappings for columns from location_supp table -->
</join>
</class>
答案 1 :(得分：0)
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="com.url.hiber.action">
<class name="AxisFandAuser" table="axisFandA_user" dynamic-insert="true" dynamic-update="true">
<id name="userId" column="userId">
<generator class="native" />
</id>
<property name="userFName" column="userFName"/>
<property name="userMName" column="userMName"/>
<property name="userLName" column="userLName"/>
<property name="username" column="username"/>
<property name="userEmailId" column="userEmailId"/>
<property name="userOfficeLNumber" column="userOfficeLNumber"/>
<property name="userExtention" column="userExtention"/>
<property name="userMNumber" column="userMNumber"/>
<property name="userPassword" column="userPassword"/>
<property name="lock" column="lock"/>
<!-- <property name="roleId" column="roleId"/>-->
<many-to-one name="axisFandARole" class="com.url.hiber.action.AxisFandARole" fetch="select">
<column name="roleId" not-null="false" />
</many-to-one>
<set name="axisFandAservice" table="axisFandA_service" inverse="true" lazy="true" fetch="select">
<key>
<column name="userId" not-null="false" />
</key>
<one-to-many class="com.url.hiber.action.AxisFandAservice" />
</set>
<set name="axisFandAgroundRule" table="axisFandA_groundRule" inverse="true" lazy="true" fetch="select">
<key>
<column name="userId" not-null="false" />
</key>
<one-to-many class="com.url.hiber.action.AxisFandAgroundRule" />
</set>
<set name="quantumLogDetail" table="axisFandA_quantumLogDetail" inverse="true" lazy="true" fetch="select">
<key>
<column name="userId" not-null="false" />
</key>
<one-to-many class="com.url.hiber.action.QuantumLogDetail" />
</set>
</class>
</hibernate-mapping>