Question

我有一个字符串NSString *Original=@"88) 12-sep-2012";或Original=@"8) blablabla";

我想只打印“）”之前的字符，以便如何找到字符“）”的索引。或者我怎么能这样做？

提前致谢。

Answer 1

NSString *str = [[yourString componentsSeparatedByString:@")"] objectAtIndex:0];

Answer 2

U可以找到字符“）”的索引，如下所示：

NSString *Original=@"88) 12-sep-2012";
NSRange range = [Original rangeOfString:@")"];
if(range.location != NSNotFound)
{
 NSString *result = [Original substringWithRange:NSMakeRange(0, range.location)];
}

Answer 3

您可以使用以下代码查看“）”

之前的字符

   // this would split the string into values which would be stored in an array
   NSArray *splitStringArray = [yourString componentsSeparatedByString:@")"];
   // this would display the characters before the character ")"
   NSLog(@"%@", [splitStringArray objectAtIndex:0]);

Answer 4

NSUInteger index = [Original rangeOfString:@")"];

NSString *result = [Original substringWithRange:NSMakeRange(0, index)];

Answer 5

尝试以下代码来获取字符串中特定字符的索引： -

NSString *string = @"88) 12-sep-2012";
NSCharacterSet *charSet = [NSCharacterSet characterSetWithCharactersInString:@")"];
NSRange range = [string rangeOfCharacterFromSet:charSet];

if (range.location == NSNotFound) 
{
    // ... oops
}
else {
    NSLog(@"---%d", range.location);
    // range.location is the index of character )
}

并获取字符串之前的字符串使用： -

NSString *str = [[string componentsSeparatedByString:@")"] objectAtIndex:0];

Answer 6

另一个解决方案：

NSString *Original=@"88) 12-sep-2012";
NSRange range = [Original rangeOfString:@")"];
NSString *result = Original;

if (range.location != NSNotFound)
{
    result = [Original substringToIndex:range.location];
}

NSLog(@"Result: %@", result);

查找字符串中字符的索引

6 个答案: