Question

我收到错误“{”类型Device1不是预期的。使用XmlInclude或SoapInclude属性指定静态未知的类型。“}”

目前我有：

public abstract class Device
{
   ..
} 

public class Device1 : Device
{ ... }

[Serializable()]
public class DeviceCollection : CollectionBase
{ ... }

[XmlRoot(ElementName = "Devices")]
public class XMLDevicesContainer
{
    private DeviceCollection _deviceElement = new DeviceCollection();

    /// <summary>Devices device collection xml element.</summary>
    [XmlArrayItem("Device", typeof(Device))]
    [XmlArray("Devices")]
    public DeviceCollection Devices
    {
        get
        {
            return _deviceElement;
        }
        set
        {
            _deviceElement = value;
        }
    }
}

我正在做：

        XMLDevicesContainer devices = new XMLDevicesContainer();
        Device device = new Device1();

        device.DeviceName = "XXX";
        device.Password = "Password";

        devices.Devices.Add(device);
        Serializer.SaveAs<XMLDevicesContainer>(devices, @"c:\Devices.xml", new Type[] { typeof(Device1) });

序列化器确实：

   public static void Serialize<T>(T obj, XmlWriter writer, Type[] extraTypes)
    {
        XmlSerializer xs = new XmlSerializer(typeof(T), extraTypes);
        xs.Serialize(writer, obj);
    }

我落在序列化程序方法的最后一行（xs.Serialize）上的错误：“{”类型Device1不是预期的。使用XmlInclude或SoapInclude属性指定静态未知的类型。“}”

我尝试在Device类上编写XmlInclude。没有帮助。如果我改变了行

    [XmlArrayItem("Device", typeof(Device))]

是

     [XmlArrayItem("Device", typeof(Device1))]

然后它可以工作，但我想编写多种设备类型的数组。

Answer 1

您必须为要在XMLDevicesContainer类上使用的每个子类添加XmlIncludeAttribute。

[XmlRoot(ElementName = "Devices")]
[XMLInclude(typeof(Device1))]
[XMLInclude(typeof(Device2))]
public class XMLDevicesContainer
{
:
}

Answer 2

按如下方式声明您的XmlSerializer：

XmlSerializer xs = new XmlSerializer(typeof(obj), extraTypes);

我之前实现的WCF Web服务遇到了同样的问题。我有(object obj)作为参数＆amp;我宣布我的XmlSerializer new XmlSerializer(typeof(object))就像new XmlSerializer(obj.GetType())一样，这是静态的。将其更改为$dateValue = strtotime($q); $yr = date("Y", $dateValue) ." "; $mon = date("m", $dateValue)." "; $date = date("d", $dateValue);解决了它。

xml序列化和继承类型

2 个答案: