Question

您好我正在使用Zeon库实现一个sftp客户端，它工作正常。当我测试失败时，问题就出现了，这是我的代码：

int status = 0;
try {
    SFTPClient sftpClient = new SFTPClient(host, username, password);
    status = sftpClient.sendFolder(sendingFolder, destFolder, new BatchTransferProgressDefault());

    System.out.println("FileTransferStatus.SUCCESS: " + FileTransferStatus.SUCCESS);
    System.out.println("status: " + status);
}catch (FileTransferException e){
    LOGGER.error(e);
}catch (Exception e2){
    LOGGER.error(e2);
}

所以我输入了错误的主机，用户名和密码，状态标志仍然返回true，即使我的控制台显示异常并且它也没有进入我的异常。

有谁知道如何强制zeon库进入我的异常块？提前致谢

Answer 1

你的问题是这可能发生了：

boolean status = true;
// ... status flag doesn't ever get set to false ...
try {
    SFTPClient sftpClient = new SFTPClient(host, username, password);
    // Your error is thrown before you get this far.
    status = sftpClient.sendFolder(sendingFolder, destFolder, new BatchTransferProgressDefault());
    System.out.println("FileTransferStatus.SUCCESS: " + FileTransferStatus.SUCCESS);
    System.out.println("status: " + status);
} catch (FileTransferException e){
    // The error is logged which means you'll only see it wherever you log it.
    LOGGER.error(e);
} catch (Exception e2){
    LOGGER.error(e2);
}

zeon java库没有捕获异常

1 个答案: