Question

我正在阅读一个有时间（小时和分钟）和IP地址的文本文件。然后我想得到时间差异并且每5分钟做一些活动。以下代码不计算时差。

示例文本文件：

06:03 65.55.215.62
06:04 157.56.92.152
06:04 66.249.74.175
06:05 173.199.116.171

代码：

time_ip = []
for line in open('minutes'):
    time_ip.append(line.split(' '))    

df = pandas.DataFrame(time_ip)
df['tvalue'] = df[0]
df['delta'] = (df['tvalue']-df['tvalue'])

Answer 1

您应该使用read_csv将csv读入DataFrame：

In [1]: df = pd.read_csv(file_name, sep='\s+', header=None, names=['time', 'ip'])

In [2]: df
Out[2]:
    time               ip
0  06:03     65.55.215.62
1  06:04    157.56.92.152
2  06:04    66.249.74.175
3  06:05  173.199.116.171

Pandas（还）没有任何内置时间对象，在python中执行此操作并不容易...您可以创建时间对象的时间列：

In [3]: df['time'] = df['time'].apply(lambda x: datetime.time(*map(int, x.split(':'))))

In [4]: df
Out[4]:
       time               ip
0  06:03:00     65.55.215.62
1  06:04:00    157.56.92.152
2  06:04:00    66.249.74.175
3  06:05:00  173.199.116.171

尤其是因为你不能做arithmetic on datetime.time objects。无论如何，我认为你不会因为年/月/日在这里而陷入困境一方面，如何应对午夜？

假设你有一个约会时间......让我们重新开始......

In [5]: df = pd.read_csv(file_name, sep='\s+', header=None, names=['time', 'ip'])

In [6]: df['time'] = pd.to_datetime(df['time'])  # let's use todays

In [7]: df
Out[7]:
                 time               ip
0 2013-06-12 06:03:00     65.55.215.62
1 2013-06-12 06:04:00    157.56.92.152
2 2013-06-12 06:04:00    66.249.74.175
3 2013-06-12 06:05:00  173.199.116.171

然后，您可以使用shift

来获取差异

In [8]: df['time'].shift()
Out[8]:
0                   NaT
1   2013-06-12 06:03:00
2   2013-06-12 06:04:00
3   2013-06-12 06:04:00
Name: time, dtype: datetime64[ns]

In [9]: d['time'] - df['time'].shift()
Out[9]:
0        NaT
1   00:01:00
2   00:00:00
3   00:01:00
Name: time, dtype: timedelta64[ns]

更容易。：）

Answer 2

您可以使用datetime模块

import datetime
with open('minutes', 'r') as myfile:
    times = myfile.read().split()[::2]
dates = [datetime.datetime.strptime(i, '%H:%M') for i in times]
differences = [j-i for i, j in zip(dates[:-1], dates[1:])]
print [divmod(i.seconds, 60)[0] for i in differences]

打印：

[1, 0, 1]

Answer 3

>>> import datetime
>>> end = datetime.datetime.now()
>>> start = datetime.datetime.now()
>>> diff
datetime.timedelta(0, 7, 424199)
>>> diff = start - end
>>> divmod(diff.days * 86400 + diff.seconds, 60)
(0, 7) # 0 minutes, 7 seconds

以分钟计算时差

3 个答案: