Question

我有这个：

public class Base {
   public virtual void Connect()
   {
      // do stuff
   }
}

public class Derived1 : Base {
   public override void Connect()
   {
       base.Connect();
      // do other stuff
   }
}

public class Derived2 : Derived {
   public override void Connect()
   {
      base.Connect() // Here I want to call Base::Connect(), not Derived::Connect()
   }
}

有没有办法可以从Derived2调用Base :: Connect，因为我想跳过Derived1 :: Connect（）中的“do other stuff”部分？

编辑：我必须从Derived1派生。

Answer 1

Yo可以尝试将Connect拆分为两个函数，并从需要它的所有派生类中调用DoConnect：

public class Base {
   public virtual void Connect()
   {
      DoConnect();
   }

   protected void DoConnect()
   {
      // do stuff
   }
}

...

public class Derived2 : Derived1 {
   public override void Connect()
   {
      DoConnect();
      ...
   }
}

如果您无法更新基类，则可以在Derived1

执行此拆分

public class Derived1 : Base {
   public virtual void Connect()
   {
      DoConnect();
   }

   protected void DoConnect()
   {
      base.Connect();
   }
}

Answer 2

C＃剂量没有提供直接的方式来调用base.base.method()首先需要更改您的设计请查看此答案why-c-sharp-doesnt-support-base-base

所以你需要改变你的设计，以便做一点技巧或解决方法。

在班级Derived1中定义一种新方法，唯一的工作就是致电base.Connect()
然后在您的班级Derived2()中定义您的Connect()，它只会调用上一步中定义的上一个函数。

检查这个例子：

public class Base {
    public virtual void Connect() {
        // do stuff
    }
}

public class Derived1: Base {
    public override void Connect() {
        base.Connect();
        // do other stuff
    }
    public void CallBaseConnnect() {
        //here make only one call to base.Connect(). 
        //that's how class Derived1 'll provide you away to call base.Connect().
        base.Connect();
    }
}

public class Derived2: Derived {
    public override void Connect() {
        //here just make a call to CallBaseConnnect() in base class Derived1
        //that 'll equivalent to base.base.Connect.
        base.CallBaseConnnect();
    }
}

从派生的派生类调用父类方法

2 个答案: