Question

$data = Array ( ['key1'] => 1 , ['key2'] => 20 , ['key3'] => 11)
$key1 = Array (1 => "a" , 2 => "b")
$key2 = Array (1 => "a" , .... 20 => "y") 
$key3 = Array (1 => "a" , .... 11 => "n")

替换$ data数组中所有值的最简单方法是返回：

$data['key1'] = $key1[$data['key1']]

而不是一个一个地做，即：

$data['key1'] = $key1[$data['key1']]
$data['key2'] = $key2[$data['key2']]...

Answer 1

我认为你正在寻找这个：

foreach($data as $k => &$v)
{
    if($$k)
    {
        $t = $$k;
        if($t[$v]) $v = $t[$v];
    }
}

print_r($data);

但我建议问自己一些关于此意图的更大问题

Answer 2

这个问题很难理解，但我认为你要做的是使用$data从其他数组中提取数据。如果是这种情况，这应该有效：

$data = array('key1' => 1, 'key2' => 2, 'key3' => 0);
$key1 = array(1,2,3,4,5);
$key2 = array(6,7,8,9,10);
$key3 = array(11,12,13,14);

foreach(array_keys($data) as $key) {
  if(isset($$key)) {
    $target = $$key;
    $value = $target[$data[$key]];

    $data[$key] = $value;
  }
}

var_dump($data); #=> [key1 => 2, key2 => 8, key3 => 11]

Answer 3

我更喜欢这个解决方案

array_walk(
    $data,
    function(&$a, $b) {
        $a = $$a[$b];
    }
);

Answer 4

您可以尝试使用PHP的变量变量，如下所示：

foreach ($data as $mkey => $mval)
{
 $data[$mkey] = $$mkey[$data[$mkey]];
}

PHP数组替换

4 个答案: