Question

将数组传递给函数

时出错

数组： int red_eachpix[MAX_PIX] = { 0 }

功能：

void sum_individualpix(int *pixels, int pixle) {
    pixels[(pixle - 1)]++;
}

错误：错误C2664：'void sum_individualpix（int，int）'：无法将参数1从'int [255]'转换为'int'

整个计划如下：

#define MAX_PIX 255
#define WIDTH 25
#define HEIGHT 25

void sum_individualpix(int , int);    // I think the error is here

int main()
{
    int X, Y, red, counter = 0;
    int red_eachpix[MAX_PIX] = { 0 }, Red[WIDTH][HEIGHT] = { 0 };
    long sum_red = 0;
    in.open("basicval.txt");
    if (in)
    {
        in >> X >> Y >> red;  //Data is in form of:   X  Y    B1(red pixel value)
        while (!in.eof())
            {
                counter++;
                sum_red += red;

                Red[X][Y] = red;

                sum_individualpix(red_eachpix, red);    //Getting Error here

                in >> X >> Y >> red;
             }

         double avg_red = (double)sum_red / counter;
         cout << "Average Value for Red = " << avg_red << endl;
    }
    in.close();
    getchar();
}

void sum_individualpix(int *pixels, int pixle) {
    pixels[(pixle - 1)]++;
}

以防万一有人想知道程序读取图像的像素值，而图像本身已被程序转换为ASCII值

已编辑： 实际上是Red[WIDTH][HEIGHT]＆amp; int X, Y, red, counter = 0;并非错误。我不小心写错了。

Answer 1

您定义了两次相同名称'red'：

int X, Y, red, counter = 0;
int red_eachpix[MAX_PIX] = { 0 }, red[WIDTH][HEIGHT] = { 0 };

Answer 2

你有int X, Y, red, counter = 0;，一个名为红色的int变量还有red[WIDTH][HEIGHT] = { 0 }; int数组，名为red

Answer 3

void sum_individualpix(int *pixels, int pixle) {
    pixels[(pixle - 1)]++; //Shows that first argument type is array
}

错误是函数声明void sum_individualpix(int , int)第一个（参数）数据类型说明符实际上是数组（int []）而不是整数（int）所以声明应该是已更改为void sum_individualpix(int[], int)

将数组作为函数参数传递时出错

3 个答案: