Question

最近我正在研究c＃中的地理位置。在互联网上没有太多关于我的信息。任何人都可以在c＃中向我发送此地理定位的链接或简短示例代码。我使用visual studio 2010.使用控制台应用程序来做。用户输入LAC，MCC，MNC，CID以及使用google api密钥查找其位置（长，纬度）。

真的很感谢帮助我。

Answer 1

检查以下代码您可以获得LAT LNG 我希望这有用：）

using System;
using System.Collections.Generic;
using System.Linq;

using System.Text;
using System.IO;
using System.Net;

namespace ConsoleApplication1
{
    public class GoogleMapsApi
    {
        static byte[] PostData(int MCC, int MNC, int LAC, int CID)
        {

        /* The shortCID parameter follows heuristic experiences:

         * Sometimes UMTS CIDs are build up from the original GSM CID (lower 4 hex digits)

         * and the RNC-ID left shifted into the upper 4 digits.

         */

        byte[] pd = new byte[] {

    0x00, 0x0e,

    0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,

    0x00, 0x00,

    0x00, 0x00,

    0x00, 0x00,

    0x1b,

    0x00, 0x00, 0x00, 0x00, // Offset 0x11

    0x00, 0x00, 0x00, 0x00, // Offset 0x15

    0x00, 0x00, 0x00, 0x00, // Offset 0x19

    0x00, 0x00,

    0x00, 0x00, 0x00, 0x00, // Offset 0x1f

    0x00, 0x00, 0x00, 0x00, // Offset 0x23

    0x00, 0x00, 0x00, 0x00, // Offset 0x27

    0x00, 0x00, 0x00, 0x00, // Offset 0x2b

    0xff, 0xff, 0xff, 0xff,

    0x00, 0x00, 0x00, 0x00

};
        Console.WriteLine(pd.Length);

        bool isUMTSCell = ((Int64)CID > 65535);

        /*    if (shortCID)

                CID &= 0xFFFF;      /* Attempt to resolve the cell using the

                            GSM CID part */

        if ((Int64)CID > 65536) /* GSM: 4 hex digits, UTMS: 6 hex

                        digits */

            pd[0x1c] = 5;

        else

            pd[0x1c] = 3;

        pd[0x11] = (byte)((MNC >> 24) & 0xFF);

        pd[0x12] = (byte)((MNC >> 16) & 0xFF);

        pd[0x13] = (byte)((MNC >> 8) & 0xFF);

        pd[0x14] = (byte)((MNC >> 0) & 0xFF);

        pd[0x15] = (byte)((MCC >> 24) & 0xFF);

        pd[0x16] = (byte)((MCC >> 16) & 0xFF);

        pd[0x17] = (byte)((MCC >> 8) & 0xFF);

        pd[0x18] = (byte)((MCC >> 0) & 0xFF);

        pd[0x27] = (byte)((MNC >> 24) & 0xFF);

        pd[0x28] = (byte)((MNC >> 16) & 0xFF);

        pd[0x29] = (byte)((MNC >> 8) & 0xFF);

        pd[0x2a] = (byte)((MNC >> 0) & 0xFF);

        pd[0x2b] = (byte)((MCC >> 24) & 0xFF);

        pd[0x2c] = (byte)((MCC >> 16) & 0xFF);

        pd[0x2d] = (byte)((MCC >> 8) & 0xFF);

        pd[0x2e] = (byte)((MCC >> 0) & 0xFF);

        pd[0x1f] = (byte)((CID >> 24) & 0xFF);

        pd[0x20] = (byte)((CID >> 16) & 0xFF);

        pd[0x21] = (byte)((CID >> 8) & 0xFF);

        pd[0x22] = (byte)((CID >> 0) & 0xFF);

        pd[0x23] = (byte)((LAC >> 24) & 0xFF);

        pd[0x24] = (byte)((LAC >> 16) & 0xFF);

        pd[0x25] = (byte)((LAC >> 8) & 0xFF);

        pd[0x26] = (byte)((LAC >> 0) & 0xFF);

        return pd;

    }

    static public string[] GetLatLng(int MCC, int MNC, int LAC, int CID)
    {

        string[] result = new string[2];

        try
        {

            String url = "http://www.google.com/glm/mmap";

            HttpWebRequest req = (HttpWebRequest)WebRequest.Create(

                new Uri(url));

            req.Method = "POST";

            byte[] pd = PostData(MCC, MNC, LAC, CID);

            req.ContentLength = pd.Length;

            req.ContentType = "application/binary";

            Stream outputStream = req.GetRequestStream();

            outputStream.Write(pd, 0, pd.Length);

            outputStream.Close();

            HttpWebResponse res = (HttpWebResponse)req.GetResponse();

            byte[] ps = new byte[res.ContentLength];

            int totalBytesRead = 0;

            while (totalBytesRead < ps.Length)
            {

                totalBytesRead += res.GetResponseStream().Read(

                    ps, totalBytesRead, ps.Length - totalBytesRead);

            }

            //for(int i=0;i<ps.Length;i++)
            //    Console.WriteLine(ps[i]);
            string r = System.Text.Encoding.UTF8.GetString(ps);
            Console.WriteLine(r);



            if (res.StatusCode == HttpStatusCode.OK)
            {

                short opcode1 = (short)(ps[0] << 8 | ps[1]);

                byte opcode2 = ps[2];

                int ret_code = (int)((ps[3] << 24) | (ps[4] << 16) |

                               (ps[5] << 8) | (ps[6]));

                if (ret_code == 0)
                {

                    double lat = ((double)((ps[7] << 24) | (ps[8] << 16)

                                 | (ps[9] << 8) | (ps[10]))) / 1000000;

                    double lon = ((double)((ps[11] << 24) | (ps[12] <<

                                 16) | (ps[13] << 8) | (ps[14]))) /

                                 1000000;

                    result[0] = lat.ToString();
                    result[1] = lon.ToString();
                    return result;

                }

                else
                {

                    return result;
                }

            }

            else

                return result;

        }

        catch (Exception ex)
        {
            result[0] = ex.Message;
            return result;

        }

    }
}
}

使用c＃中的LAc，MNC，MCC，CID查找坐标的示例代码

1 个答案: