MySQL查询不对计算值进行排序

Question

我有一个更长，更复杂的代码，我希望从表中获得最新的条目，但我收到最旧的一个。我尝试过：MIN(date), Max(date) desc和asc。它不起作用。我的代码是否需要特殊的解决方案？

SELECT stock_id,
       stocks.name,
       DATE_FORMAT(date, '%Y-%m-%d %H:%i:%s') AS date,
       price, pxchange,
       CONCAT(round(pxpct*100, 4), '%') AS pxpct, 
       stocks.stockmarket, 
       stockmarkets.id
FROM   (SELECT CASE WHEN stock_id <> @pxticker THEN @pxclose := NULL END,
               p.*, 
               (price - @pxclose) AS pxchange, 
               (price - @pxclose) / @pxclose AS pxpct, 
               (@pxclose := price), 
               (@pxticker := stock_id)
        FROM   quotations p CROSS JOIN 
               (SELECT @pxclose := NULL, @pxticker := stock_id
                FROM   quotations
                ORDER  BY stock_id, date
                LIMIT  1) AS a
        ORDER  BY stock_id, date) AS b
LEFT   JOIN stocks       ON stock_id = stocks.id
LEFT   JOIN stockmarkets ON stockmarkets.id = stocks.stockmarket 
WHERE  stocks.stockmarket = (SELECT id FROM stockmarkets WHERE short ='".$q."')
GROUP  BY stock_id
ORDER  BY stock_id, MIN(date) ASC

我正在思考和工作几个小时，经过尝试和尝试。但似乎没有任何帮助。

感谢任何可以提供帮助的人。如果我的吸收速度很慢，我不会感到惊讶。

- 编辑 - 示例

我得到但不想要的。

4   Facebook, Inc.          2014-02-24 14:43:49     7   NULL    NULL    1   1
5   Tesla Motors, Inc.  2014-02-24 14:59:28     7   NULL    NULL    1   1

我想要的（样本值，日期 - 时间戳 - 很重要）。

4   Facebook, Inc.          2014-03-10 22:33:39     50  NULL    NULL    1   1
5   Tesla Motors, Inc.  2014-03-10 22:52:28     20  NULL    NULL    1   1

根据上面的语法，我想得到我连接到纳斯达克的每一只股票的最新报价（在这个例子中）。但我总是得到我在表格'引用'中插入的最早的第一个引文。

EDIT

编辑2 - 代码

SELECT stock_id,
       stocks.name,
       DATE_FORMAT(date, '%Y-%m-%d %H:%i:%s') AS date,
       price, pxchange,
       CONCAT(round(pxpct*100, 4), '%') AS pxpct, 
       stocks.stockmarket, 
       stockmarkets.id
FROM   (SELECT CASE WHEN stock_id <> @pxticker THEN @pxclose := NULL END,
               p.*, 
               (price - @pxclose) AS pxchange, 
               (price - @pxclose) / @pxclose AS pxpct, 
               (@pxclose := price), 
               (@pxticker := stock_id)
        FROM   quotations p CROSS JOIN 
               (SELECT @pxclose := NULL, @pxticker := stock_id
                FROM   quotations
                ORDER  BY date, stock_id
                LIMIT  1) AS a
        ORDER  BY date, stock_id) AS b
LEFT   JOIN stocks       ON stock_id = stocks.id
LEFT   JOIN stockmarkets ON stockmarkets.id = stocks.stockmarket 
WHERE  stocks.stockmarket = (SELECT id FROM stockmarkets WHERE short ='NASDAQ')
GROUP  BY stock_id
ORDER  BY date, stock_id

这是一个小提琴：http://www.sqlfiddle.com/#!2/ff809/44 不完全相同的数据，但我正在使用的代码。还有同样的问题：如何获得最新的条目？

EDIT - 有关结构信息的屏幕截图 以下是有关所用表格的内容和结构的屏幕截图。也许有帮助。

Answer 1

如果您想要最早的记录，那么order by子句应首先具有日期。 更改以下

ORDER BY stock_id, date DESC

与

ORDER BY date DESC, stock_id