Question

My Table gainfinal包含三个列 - countrycode，year和values。我想选择前十个值的十行。首先，我使用以下查询根据值创建了一个排名。

    SELECT countrycode, `values`,
    @curRank := @curRank + 1 AS rank
    FROM gainfinal CROSS JOIN
    (SELECT @curRank := 0) vars
    WHERE year = 2000
    ORDER By `values` DESC ;

现在，我需要选择排名最高的前十行。我该怎么做？

Answer 1

SELECT countrycode, `values`,
@curRank := @curRank + 1 AS rank
FROM gainfinal CROSS JOIN
(SELECT @curRank := 0) vars
WHERE year = 2000
ORDER By `values` DESC
LIMIT 10;

Answer 2

使用

LIMIT

SQL中的

例如：

SELECT countrycode, `values`,
@curRank := @curRank + 1 AS rank
FROM gainfinal CROSS JOIN
(SELECT @curRank := 0) vars
WHERE year = 2000
ORDER By `values` DESC
LIMIT 10

Answer 3

你可以使用：Limit

从第20行开始获得10行

LIMIT 10 OFFSET 20 --Equivalent to LIMIT 20, 10

Answer 4

您还可以在where语句

中使用rank变量

...WHERE year = 2000 and @curRank <11;

选择MySQL中的前十行

4 个答案: