Question

所以这是我的应用程序的一般流程：

Main Menu - ＆gt; Account Manager - ＆gt; Account Details - ＆gt; Payment Schedule

Account Manager中用户选择的数据通过Account Details传递给Serialized Object。然后从Account Details开始，Serialized Object将Payment Schedule传递给PayTable进行计算，所有结果都会专门投入我的数据库{.1}}。

每个帐户都可以有多笔付款，以确保我可以将正确的付款条目与我GroupID中PayTable的正确帐户相关联。因此，现在PayTable中的条目被分配了GroupID，该AccountID基于传递给AccountsTable的{{1}}中的Payment Schedule。

所以，如果AccountID = 1然后GroupID = 1。

使用此功能，我可以过滤掉正确帐户的正确付款，然后在GridView Payments Schedule中显示。

编辑（删除了大部分不再重要的旧帖子，但将我的情况的要点放在首位以供参考）

摘要

我有两张表Account和Payment。 Account colID Payment GroupID GroupID colID。 colID取决于所选帐户的GroupID。因此，如果GroupID说3，那么该实例中的所有付款条目也将被分配{3}的colID，因此我可以将正确的付款与正确的帐户配对。

问题是我需要比较两个字段（db.execSQL("CREATE VIEW " + viewPayments + " AS SELECT " + payTable + "." + colPayID + " AS _id," + " " + accountsTable + "." + colID + "," + " " + payTable + "." + colGroupID + "," + " " + payTable + "." + colPayBal + "," + " " + payTable + "." + colInterest + "," + " " + payTable + "." + colPayDue + "," + " " + payTable + "." + colDateDue + "," + " " + payTable + "." + colPaid + "" + " FROM " + payTable + " JOIN " + accountsTable + " ON " + payTable + "." + colGroupID + " = " + accountsTable + "." + colID ); == Cursor filterpay(String Payment) { SQLiteDatabase db = this.getWritableDatabase(); String[] columns = new String[]{"_id", colGroupID, colPayBal, colInterest, colPayDue, colDateDue, colPaid}; Cursor c = db.query(viewPayments, columns, colGroupID + "=?", new String[]{Payment}, null, null, null); return c;）并获取与条件匹配的所有条目。所以这意味着两个表中两个字段的交叉比较。

解决方案

使用INNER JOIN并创建了一个更简单的GridView引用视图：

TextView txt;
txt = (TextView)findViewById(R.id.putithere);
txt.setVisibility(View.GONE);

public void Paygrid(){

dbHelper = new DatabaseHelper(this);
String Payment = String.valueOf(txt.getText());
Cursor a = dbHelper.filterpay(Payment);
startManagingCursor(a);

String[] from = new String[]{DatabaseHelper.colPayBal, DatabaseHelper.colInterest, DatabaseHelper.colPayDue, DatabaseHelper.colDateDue, DatabaseHelper.colPaid};
int[] to = new int[]{R.id.Amount,R.id.Interest, R.id.Total, R.id.DateDue, R.id.Paid};

SimpleCursorAdapter saa = new SimpleCursorAdapter(this, R.layout.paygrid, a, from, to);
intgrid.setAdapter(saa);

修正了我的查询
```
txt
```
最后但并非最不重要的是，调整我的代码以便在我的GridView上发布。
```
colID
```
}

{{1}}这些东西只是我懒得找到一个更清晰的方法来获取帐户的{{1}}并在我的'PayGrid'中引用它所以我可能不会建议我看待。

此外，因为我是新来的，所以当我回答我自己的问题时，我不知道如何将这个问题标记为已回答，所以如果有人能够指出那就好了。除此之外，我希望这可以帮助将来的某个人。欢呼声。

另一方面，感谢随意的人！非常感谢您的帮助。

Answer 1

我刚看到＆＃34;回答你的问题＆＃34;页面底部的按钮在编辑后发布我自己的解决方案....是的，当我这样做时，我做了facepalm。

<强>解决方案

使用INNER JOIN并创建了一个更简单的GridView引用视图：

db.execSQL("CREATE VIEW " + viewPayments +
                " AS SELECT " + payTable + "." + colPayID + " AS _id," +
                " " + accountsTable + "." + colID + "," +
                " " + payTable + "." + colGroupID + "," +
                " " + payTable + "." + colPayBal + "," +
                " " + payTable + "." + colInterest + "," +
                " " + payTable + "." + colPayDue + "," +
                " " + payTable + "." + colDateDue + "," +
                " " + payTable + "." + colPaid + "" +
                " FROM " + payTable +
                " JOIN " + accountsTable + " ON " + payTable + "." + colGroupID + " = " + accountsTable + "." + colID );

修正了我的查询

Cursor filterpay(String Payment) {
    SQLiteDatabase db = this.getWritableDatabase();
    String[] columns = new String[]{"_id", colGroupID, colPayBal, colInterest, colPayDue, colDateDue, colPaid};
    Cursor c = db.query(viewPayments, columns, colGroupID + "=?", new String[]{Payment}, null, null, null);
    return c;

最后但并非最不重要的是，调整我的代码以便在我的GridView上发布。

TextView txt;
txt = (TextView)findViewById(R.id.putithere);
txt.setVisibility(View.GONE);

public void Paygrid(){

dbHelper = new DatabaseHelper(this);
String Payment = String.valueOf(txt.getText());
Cursor a = dbHelper.filterpay(Payment);
startManagingCursor(a);

String[] from = new String[]{DatabaseHelper.colPayBal, DatabaseHelper.colInterest, DatabaseHelper.colPayDue, DatabaseHelper.colDateDue, DatabaseHelper.colPaid};
int[] to = new int[]{R.id.Amount,R.id.Interest, R.id.Total, R.id.DateDue, R.id.Paid};

SimpleCursorAdapter saa = new SimpleCursorAdapter(this, R.layout.paygrid, a, from, to);
intgrid.setAdapter(saa);

}

txt这些东西只是我懒得找到一个更清晰的方式来获取帐户的colID并在PayGrid中引用它，所以我可能不会推荐在这方面跟着我。

根据另一个表的值查询表

1 个答案: