Question

所以我要创建一个程序来验证密码是否正确创建。要通过验证，用户必须输入6个或更多字符，至少包含一个小写字母，一个大写字母和一个数字。问题是我必须只使用cstring（当然还有cctype）库而不是字符串库。如果用户创建了错误的密码，程序运行正常，如果他们成功创建了一个好的密码，那么它有时（不确定为什么有时会）崩溃。对此的回答将帮助我巩固我对指针的理解更多的内存分配是动态的。这就是有问题的程序。

#include <iostream>
#include <cctype>
#include <cstring>

bool isVerifyAccepted(char*, int);

using namespace std;

int main() {
    const int SIZE = 6;
    char *userPass = new char[SIZE];

    cout << "Verify you have a good password\na good password has to be at least six characters long\n" 
     << "have at least on uppercase and one lowercase letter and at least one digit" <<endl <<endl;

    cout << "enter a password below" <<endl <<endl;
    cin >> userPass;

    int userSizePass = strlen(userPass);  
    char testPassWord[userSizePass];      

    int count = 0;
    while (count < userPass[count]) {
        testPassWord[count] = userPass[count];
        count++;
    }

    isVerifyAccepted(testPassWord, userSizePass);


    delete[] userPass;
    userPass = NULL;

    //system("pause");
    return 0;
}

bool isVerifyAccepted(char *pass, int size){
    bool verify[3];
    if(size <= 6){
       cout << "Password is too short "<<endl;
       return false;
    }

    for(int i = 0; i<size; i++){
        if(islower(pass[i])){
           verify[0] = true;
           break;
        }else{
           verify[0] = false;      
        }  
    }

    for(int i = 0; i<size; i++){
        if(isupper(pass[i])){
           verify[1] = true;
           break;
        }else{
           verify[1] = false;      
        }  
    }

    for(int i = 0; i<size; i++){
        if(isdigit(pass[i])){
            verify[2] = true;
            break;
        }else{
            verify[2] = false;      
        }  
    }

    if(verify[0] == false){
        cout << "You need at least one lowercase letter" << endl;          
    }

    if(verify[1] == false){
        cout << "You need at least one uppercase letter" << endl;          
    }

    if(verify[2] == false){
       cout << "You need at least one digit" << endl;          
    }

    if((verify[0] == true) && (verify[1] == true) && (verify[2] == true)){
       cout << "You have a good password, you met the criteria " <<endl;
    }

    return verify;     
}

Answer 1

因为根据调试器的这一行：const int SIZE = 6。

将尺寸增加到32或大于6的某个数字。有些密码超过6个字符。

我的程序有时会崩溃C ++？

1 个答案: