如何通过curl调用使用HTTP请求发送标头？

Question

我希望在Linux机器上向我的Apache服务器发送一个标头。如何通过卷曲调用来实现这一目标？

Answer 1

man curl：

   -H/--header <header>
          (HTTP)  Extra header to use when getting a web page. You may specify
          any number of extra headers. Note that if you should  add  a  custom
          header that has the same name as one of the internal ones curl would
          use, your externally set header will be used instead of the internal
          one.  This  allows  you  to make even trickier stuff than curl would
          normally do. You should not replace internally set  headers  without
          knowing  perfectly well what you're doing. Remove an internal header
          by giving a replacement without content on the  right  side  of  the
          colon, as in: -H "Host:".

          curl  will  make sure that each header you add/replace get sent with
          the proper end of line marker, you should thus not  add  that  as  a
          part  of the header content: do not add newlines or carriage returns
          they will only mess things up for you.

          See also the -A/--user-agent and -e/--referer options.

          This option can be used multiple times to add/replace/remove  multi-
          ple headers.

示例：

curl --header "X-MyHeader: 123" www.google.com

您可以通过添加-v选项查看发送卷曲的请求。

Answer 2

获取：

使用JSON：

curl -i -H "Accept: application/json" -H "Content-Type: application/json" http://hostname/resource

使用XML：

curl -H "Accept: application/xml" -H "Content-Type: application/xml" -X GET http://hostname/resource

发表：

用于发布数据：

curl --data "param1=value1&param2=value2" http://hostname/resource

用于文件上传：

curl --form "fileupload=@filename.txt" http://hostname/resource

RESTful HTTP Post：

curl -X POST -d @filename http://hostname/resource

登录网站（auth）：

curl -d "username=admin&password=admin&submit=Login" --dump-header headers http://localhost/Login
curl -L -b headers http://localhost/

Answer 3

在 PHP ：

中

curl_setopt($ch, CURLOPT_HTTPHEADER, array('HeaderName:HeaderValue'));

或者您可以设置多个：

curl_setopt($ch, CURLOPT_HTTPHEADER, array('HeaderName:HeaderValue', 'HeaderName2:HeaderValue2'));

Answer 4

使用-H or --header。

手册页：http://curl.haxx.se/docs/manpage.html#-H

Answer 5

GET（多个参数）：

curl -X  GET "http://localhost:3000/action?result1=gh&result2=ghk"

或

curl --request  GET "http://localhost:3000/action?result1=gh&result2=ghk"

或

curl  "http://localhost:3000/action?result1=gh&result2=ghk"

或

curl -i -H "Application/json" -H "Content-type: application/json"  "http://localhost:3000/action?result1=gh&result2=ghk"

Answer 6

我已经从卷曲切换到Httpie;语法如下：

http http://myurl HeaderName:value

Answer 7

如果您想发送自定义标题，可以这样做：

curl -v -H @{'custom_header'='custom_header_value'} http://localhost:3000/action?result1=gh&result2=ghk

Answer 8

您还可以发送多个标头，数据（例如JSON），并在单个CUrl调用中指定Call方法（POST，GET），如下所示：

curl -X POST(Get or whatever) \
  http://your_url.com/api/endpoint \
  -H 'Content-Type: application/json' \
  -H 'header-element1: header-data1' \
  -H 'header-element2: header-data2' \

......更多标题.........

  -d '{
  "JsonExArray": [
    {
      "json_prop": "1",
    },
    {
      "json_prop": "2",
    }
  ]
}'

Answer 9

我用邮递员。

执行您想执行的任何呼叫。然后，邮递员提供了一个方便的工具来显示卷曲代码。

在终端中运行它。  

Answer 10

在 anaconda 环境中，通过 windows 命令应为： GET，例如：

curl.exe http://127.0.0.1:5000/books 

发布或修补数据，例如：

curl.exe http://127.0.0.1:5000/books/8 -X PATCH -H "Content-Type: application/json" -d '{\"rating\":\"2\"}' 

PS：为json数据添加反斜杠，以避免此类错误=> Failed to decode JSON object: Expecting value: line 1 column 1 (char 0)

并使用curl.exe代替curl只是为了避免此问题：

Invoke-WebRequest : Cannot bind parameter 'Headers'. Cannot convert the "Content-Type: application/json" value of type
"System.String" to type "System.Collections.IDictionary".
At line:1 char:48
+ ... 0.1:5000/books/8 -X PATCH -H "Content-Type: application/json" -d '{\" ...
+                                  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : InvalidArgument: (:) [Invoke-WebRequest], ParameterBindingException
    + FullyQualifiedErrorId : CannotConvertArgumentNoMessage,Microsoft.PowerShell.Commands.InvokeWebRequestCommand