Question

我正在以这种格式2.00获得价值。我想将值显示为2。我怎样才能使用php？我从数据库获取价值的代码如下，我正在使用floor函数，但evrytime我得到了值0。

码

while ($row = oci_fetch_array($rcv, OCI_ASSOC+OCI_RETURN_NULLS))$basic_info[]=$row;
foreach ($basic_info as $x)
{
$serial=$x['SERIAL'];   
$in = floor($serial);
}
 echo "$in"

数据库中的值：

2.00

所需的输出：

2

currentoutput：

0

Answer 1

使用number_format()代替

number_format($x['SERIAL'], 0);

Answer 2

您可以在$in中转换int值。

while ($row = oci_fetch_array($rcv, OCI_ASSOC+OCI_RETURN_NULLS))$basic_info[]=$row;
foreach ($basic_info as $x)
{
$serial=$x['SERIAL'];   
$in = floor($serial);
}
 echo (int)$in; // here is change.

Answer 3

使用类型转换。

<div data-dojo-type="dojo/data/ItemFileWriteStore" data-dojo-id="jsonStore_3" data-dojo-props="url:'test.do?businessId=${approvalProcess.businessId}'">
    <script type="dojo/connect" data-dojo-event="onNew" data-dojo-args="newItem">
        insertApprovalNotificationHandler(this,newItem);
    </script> 
</div>

<table data-dojo-type="dojox.grid.DataGrid"
                        data-dojo-id="grid_3" id="grid_3" 
                        store="jsonStore_3" 
                        query="{ recipientName: '*' }" 
                        rowsPerPage="20" rowSelector="20px"
                        region="center"
                        style="width: 100%;">
</table>

<script>
    var test = function() {
        jsonStore_3.newItem({sample1: 'aa', sample2:'bb'});        
    }

    var insertApprovalNotificationHandler = function (object,newItem){
        console.log("TEST");
    }
</script>

或者

$in = intval($serial);

Answer 4

while（$ row = oci_fetch_array（$ rcv，OCI_ASSOC + OCI_RETURN_NULLS））$ basic_info [] = $ row; foreach（$ basic_info as $ x）{$ serial = $ x ['SERIAL'];
$ in =（int）$ serial;} echo“$ in”;

在php中拆分小数位

4 个答案: