多字PHP数组替换

Question

<?php
$string = 'The quick brown fox jumped over the lazy dog.';
$patterns[0] = '/quick/';
$patterns[1] = '/brown/';
$patterns[2] = '/fox/';
$replacements[0] = 'slow';
$replacements[1] = 'black';
$replacements[2] = 'bear';
echo preg_replace($patterns, $replacements, $string);
?>

好的伙计们， 现在我有上面的代码。它运作良好。 现在举个例子我想用“慢”代替“懒”和“狗”我现在要做的就是这样，对吧？

<?php
$string = 'The quick brown fox jumped over the lazy dog.';
$patterns[0] = '/quick/';
$patterns[1] = '/brown/';
$patterns[2] = '/fox/';
$patterns[3] = '/lazy/';
$patterns[4] = '/dog/';
$replacements[0] = 'slow';
$replacements[1] = 'black';
$replacements[2] = 'bear';
$replacements[3] = 'slow';
$replacements[4] = 'slow';
echo preg_replace($patterns, $replacements, $string);
?>

确定。

所以我的问题是，我有什么方法可以这样做

$patterns[0] = '/quick/', '/lazy/', '/dog/';
$patterns[1] = '/brown/';
$patterns[2] = '/fox/';
$replacements[0] = 'slow';
$replacements[1] = 'black';
$replacements[2] = 'bear';

由于

Answer 1

您可以使用"Alternation"的管道：

$patterns[0] = '/quick|lazy|dog/';

Answer 2

为什么不使用str_replace？

$output = str_replace(array('quick', 'brown', 'fox'), array('lazy', 'white', 'rabbit'), $input)

Answer 3

您也可以像这样分配数组：

$patterns = array('/quick/','/brown/','/fox/','lazy/',/dog/');

当然分配0-4