Question

所以我得到了这段代码，它猜到了0到100之间的数字。它会提示一个号码，用户回答“＆＃39; h＆＃39; ＆＃39;升＆＃39;或者＆＃39; c＆＃39;

现在一切正常，只是我希望这条线只显示当用户输入不等于＆＃39; h＆＃39;，＆＃39; l＆＃39;或者＆＃39; c＆＃39;相反，即使我进入＆＃39; c＆＃39;这会破坏循环，对吗？

print "Sorry, I did not understand your input."

完整代码

start = 0
end = 100
guess = int((start+end)/2.0)
print "Please think of a number between 0 and 100!"
print


x= 'n'

while x != 'c':

    print 'Is your secret number ' + str(guess) + '?'
    x = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly.").lower()
    if x == 'h':
        end = guess
    elif x == 'l':
        start = guess
    else: 
        print "Sorry, I did not understand your input."
guess = int((start + end)/2)

print 'your answer is: ' + str(guess)

所以要澄清这是输出，即使我输入＆＃39; c＆＃39;

Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess     is too low. Enter 'c' to indicate I guessed correctly.c

Sorry, I did not understand your input.

你的答案是：50

Answer 1

elif案例没有'c'，因此属于最终else。

添加，以下处理该情况并打破while循环：

elif x == 'c':
    break

此外，您可以执行while True:并循环直到c休息。

您的更高/更低逻辑也是向后的。例如，对于h，start = guess。

guess的更新应该在while循环中缩进。

虽然循环没有正确终止

1 个答案: