Question

我的表格如下所示

     project|issue|status   |story_points|sprint |date      |active_sprint
     ===============================================
     FB1    |abc  |In Review|     3      |Backlog|2017-06-05|True 
     FB1    |acc  |In Review|     3      |Backlog|2017-06-05|True
     FB1    |adc  |In Review|     3      |Backlog|2017-06-04|True
     FB2    |xyz  |In Review|     3      |Backlog|2017-06-05|True

预期结果

     open|project|date
     ===============================================
     6   |FB1    |2017-06-05
     3   |FB1    |2017-06-04
     3   |FB2    |2017-06-05

我已经尝试了很长一段时间并且看了一遍，但仍然无法弄明白这一点。我对postgres和观点都相当新，并希望得到一些帮助。我已经尝试了很多不同的变体，但我仍然无法使其发挥作用。

    SELECT
    (SELECT COALESCE(SUM(story_points),0) AS "Open" from sample_table WHERE project = 'FB1' AND active_sprint='True' AND (status = 'In Review')) as "Open",
    (SELECT 'FB1'::text AS "Project") as "Project",
    (SELECT date as Date) as Date from sample_table WHERE project = 'FB1' group by 3

Answer 1

您可以尝试这样的事情：

select project, date1 , sum(story_points) 
from asd1
group by project, date1

Postgres视图 - 将日期相同的所有值相加

1 个答案: