if条件的按钮

时间:2017-10-21 05:59:02

标签: java android android-layout android-button

我是Android新手,我正试图打开一个按钮打开2个活动,但不适合我。 对于前: 在Mainacitivitybtn_mathematicsbtn_physics打开相同的活动(Main2acitivity)并找到btn_semester1btn_semester2,每个按钮都会打开2学期模块的其他活动。

如果用户点击了Mainacitivity,请点击: btn_mathematics ---> btn_semester1 --->将有ModulesMAT 如果点击btn_semester1相同的按钮: btn_physics ---> btn_semester1 --->将有ModulesPHY

MainActivity XML:

<Button
    android:id="@+id/btn_mathematics"
    android:onClick="btn_mathematics"
    android:text="@string/btn_mathematics/>

<Button
    android:id="@+id/btn_physics"
    android:onClick="btn_physics"
    android:text="@string/btn_physics"/>

Main2Activity XML:

<Button
    android:id="@+id/btn_semester1"
    android:onClick="btn_semester1"
    android:text="@string/btn_semester1"/>

<Button
    android:id="@+id/btn_semester2"
    android:onClick="btn_s2"
    android:text="@string/btn_semester2"/>

我想没有必要为ModulesMAT和ModulesPHY添加xml,它与其他的非常相似。

现在是java代码:

MainActivity.java:

@Override
protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }

    public void btn_mathematics (View v)  {
        Intent intent = new Intent(MainActivity.this, Main2Activity.class);
        startActivity(intent);
    }

    `public void btn_physics (View v) {
        Intent intent = new Intent(MainActivity.this, Main2Activity.class);
        startActivity(intent);
    }


}

Main2Activity.java:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main2);
}



public void btn_semester1 (View v)
{
    Intent i = getIntent();
    String id = i.getStringExtra("id");
    if(id == "btn_mathematics")
    {
         i = new Intent(this, ModulesMAT.class);
        startActivity(i);
    }
    else if (id == "btn_physics")
    {
         i = new Intent(this, ModulesPHY.class);
        startActivity(i);
    }

}


public void btn_semester2 (View v)
{
    Intent i = getIntent();
    String id = i.getStringExtra("id");
    if(id == "btn_mathematics")
    {
        i = new Intent(this, ModulesMAT2.class);
        startActivity(i);
    }
    else if (id == "btn_physics")
    {
        i = new Intent(this, ModulesPHY2.class);
        startActivity(i);
    }

}

1 个答案:

答案 0 :(得分:1)

在MainActivity中,您可以将用于识别的ID传递给Main2Activity 的 MainActivity

   public void btn_mathematics (View v)  {
        Intent intent = new Intent(MainActivity.this, Main2Activity.class);
        Bundle bundle = new Bundle();
        bundle.putString("id","Math");
        intent.putExtra(bundle);
        startActivity(intent);
    }

public void btn_physics (View v) {
    Intent intent = new Intent(MainActivity.this, Main2Activity.class);
    Bundle bundle = new Bundle();
    bundle.putString("id","Physics");
    intent.putExtra(bundle);
    startActivity(intent);
}

<强> Main2Activity

String id;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main2);

    Bundle bundle = getIntent().getExtras();
    id= bundle.getString("id");
}

public void btn_semester1 (View v)
{
    if(id == "Math")
    {
        i = new Intent(this, ModulesMAT2.class);
        startActivity(i);
    }
    else if (id == "Physics")
    {
        i = new Intent(this, ModulesPHY2.class);
        startActivity(i);
    }

}


public void btn_semester2 (View v)
{
    if(id == "Math")
    {
        i = new Intent(this, ModulesMAT2.class);
        startActivity(i);
    }
    else if (id == "Physics")
    {
        i = new Intent(this, ModulesPHY2.class);
        startActivity(i);
    }

}