Question

实施例

from somelib import Punch, Kick, Throw, Dropkick, Uppercut

globals()[class_name](x, y)
line = getline("Attacks.txt", count)
line = line.rstrip()
linelist = line.split()

class_name = linelist[1]
value = linelist[2]

class_object = globals()[class_name]
item = class_object(value)

# or shortly in one line:
# item = globals()[linelist[1]](linelist[2])

我想检查my_list上的任何字词是否在描述中，如果是，请不要做任何事情。如果my_list不在说明中，我想返回字符串＆＃39;未找到的关键字＆＃39;。

我将如何编写此代码？

Answer 1

您可以将all与双列表理解结合使用：

description = ['This is a random sentence. I like to travel and stuff','Hello world', 'Things on my bucket list, travel']
my_list = ['travel','fire']
def response():
   return "found" if any(i in b for i in my_list for b in description) else "Keywords not found"

Answer 2

保存集合中的单词并检查my_list中的单词是否在集合中。当my_list中没有短语时，此仅有效。即my_list中的所有单词都是单字组。

description = ['This is a random sentence. I like to travel and stuff','Hello world', 'Things on my bucket list, travel']
my_list = ['travel','fire']
set_words_in_description = set()
for s in description:  
    # add new words in set_words_in_description
    set_words_in_description.update(set(w for w in s.split()))

使用isdisjoint

def find_word_method_disjoint(my_list, set_words_in_description):
    # check if my_list is disjoint with set_wrods_in_description
    return not set_words_in_description.isdisjoint(my_list)

%timeit find_word_method_disjoint(my_list, set_words_in_description)
189 ns ± 1.53 ns per loop (mean ± std. dev. of 7 runs, 10000000 loops each)

%timeit response()  # function given by the accepted answer.
572 ns ± 9.3 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

Answer 3

您可以使用re.findall()从description中的句子中提取所有单词，并检查其中是否存在my_list中的任何单词：

import re

def find_words(words, text):
    desc_words = re.findall(r'[^\s,.]+', "".join(text))

    for word in words:
        if word in desc_words:
            return "found"

    return "Keywords not found"

哪个输出：

>>> description = ['This is a random sentence. I like to travel and stuff','Hello world', 'Things on my bucket list, travel']
>>> my_list = ['travel','fire']
>>> find_words(my_list, description)
found

或者您可以使用此set()方法：

def find_words(words, text):
    return "found" if set(words).intersection(re.findall(r'[^\s,.]+', "".join(text))) else "Keywords not found"

注意：如果您遇到,.以外的不同标点符号的句子，则必须更新正则表达式。

Answer 4

你可以尝试设置这样的东西吗？

description = ['This is a random sentence. I like to travel and stuff','Hello world', 'Things on my bucket list, travel']

my_list = ['travel','fire']

flat=[k for i in description for k in i.split()]


print(any({i}.issubset(set(flat))for i in my_list))

输出：

True

如何检查字符串列表是否在另一个字符串列表中？

4 个答案: