Question

我有以下sql查询：

SELECT
  distinct(date(survey_results.created_at)),
  ROUND(
    COUNT(*) FILTER (WHERE (
      scores#>>'{medic,social,total}' in('high', 'medium'))) OVER(order by date(survey_results.created_at)
    ) * 1.0 /
    (CASE (COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('high','medium','low') or coalesce(raw#>>'{survey, denied}', 'f') = 'true')) OVER(order by date(survey_results.created_at)))
    WHEN 0.0 THEN 1.0
    ELSE (COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('high','medium','low') or coalesce(raw#>>'{survey, denied}', 'f') = 'true')) OVER(order by date(survey_results.created_at)))
    END)* 100, 2
  ) AS positive,


  ROUND(
    COUNT(*) FILTER (WHERE (
      scores#>>'{medic,social,total}' in('low'))) OVER(order by date(survey_results.created_at)
    ) * 1.0 /
    (CASE (COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('high','medium','low') or coalesce(raw#>>'{survey, denied}', 'f') = 'true')) OVER(order by date(survey_results.created_at)))
    WHEN 0.0 THEN 1.0
    ELSE (COUNT(*) FILTER (WHERE (scores#>>'{medic,social,total}' in('high','medium','low') or coalesce(raw#>>'{survey, denied}', 'f') = 'true')) OVER(order by date(survey_results.created_at)))
    END)* 100, 2
  ) AS negative

  FROM survey_results
  GROUP BY date, scores, raw
  ORDER BY date ASC;

我试图让它变得更干爽和可读。有什么建议吗？

Answer 1

对于positive，您可以尝试以下逻辑：

AVG(CASE WHEN scores#>>'{medic,social,total}' in ('high', 'medium')
         THEN 100.0
         WHEN scores#>>'{medic,social,total}' in ('low')
         THEN 0.0
    END) OVER (ORDER BY date(survey_results.created_at) as positive

（negative的类似逻辑。）

我认为这封装了你的逻辑，除了当没有匹配时它返回NULL而不是0。如果这是一个问题，您可以使用COALESCE()。

使postgresql查询更具可读性

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