Question

我需要将两个表连接在一起。加入后，我想比较50个不同的列，并列出列不匹配的每一行。有没有比解决这个问题更简单的方法

SELECT * 
FROM TABLE1 T1 
   INNER JOIN TABLE2 T2 ON 
   TABLE1.ID = TABLE2.ID 
WHERE T1.NAME <> T2.NAME 
   OR T1.DESCRIPTION <> T2.DESCRIPTON --48 more comparisons

Answer 1

我认为没有一种优雅的方法可以执行此操作，但是您可以将表模式相互比较，并在列名称上进行内部联接，以生成两个表共享的列的列表。像这样：

data

然后编写一个动态查询，该查询使用该列名称列表进行比较。

Answer 2

您可以使用UNION。

--sample tables
WITH tb1 as
    (select 111 as id, 1 as a, 2 as b union all select 112 as id, 3 as a, 4 as b),

    tb2 as
    (select 111 as id, 1 as a, 2 as b union all select 112 as id, 3 as a, 5 as b),
  --  
    tablesunion as 

    (select * from tb1 union
    select * from tb2),
    tableseq as
    (SELECT ROW_NUMBER() OVER(PARTITION BY ID ORDER BY ID) AS SEQ,
            *
     FROM tablesunion)
    SELECT tb1.*, tb2.*
    FROM   tableseq s
    inner join tb1
    on (s.id = tb1.id)
    inner join tb2
    on (s.id = tb2.id)
    WHERE  seq > 1;

结果将是：

id  a   b   id  a   b
112 3   4   112 3   5

比较两个不同表中的所有列

2 个答案: