Question

我想使用C＃代码创建1095个电子文件xml。为此，我要创建动态标签，这意味着如果有可用数据，则仅创建标签，否则将无法显示该标签。

Answer 1

这里是使用xml linq创建xml文件的示例。您可以根据需要添加IF语句，以跳过添加任何元素

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            string header = "<?xml version=\"1.0\" encoding=\"utf-8\" ?><root xmlns:irs=\"myUrl\"></root>";

            XDocument doc = XDocument.Parse(header);
            XElement root = doc.Root;
            XNamespace irs = root.GetNamespaceOfPrefix("irs");

            XElement businessName = new XElement("BusinessNameLine1Txt", "Comp Name");
            root.Add(businessName);

            XElement tinRequest = new XElement(irs + "TINRequestTypeCd");
            root.Add(tinRequest);

            XElement employerEIN = new XElement(irs + "EmployerEIN", "899090900");
            root.Add(employerEIN);

            XElement contactNameGrp = new XElement("ContactNameGrp");
            root.Add(contactNameGrp);

            XElement firstName = new XElement("PersonFirstNm", "First Name Person");
            contactNameGrp.Add(firstName);

            XElement lastName = new XElement("PersonLastNm", "Last Name Person");
            contactNameGrp.Add(lastName);
        }
    }
}
//sample output
//<?xml version="1.0" encoding="utf-8" ?>
//<root xmlns:irs="myUrl">
//<BusinessName>
//  <BusinessNameLine1Txt>Comp Name</BusinessNameLine1Txt>
//</BusinessName> 
//<irs:TINRequestTypeCd>BUSINESS_TIN</irs:TINRequestTypeCd> 
//<irs:EmployerEIN>899090900</irs:EmployerEIN> 
//<ContactNameGrp>
//  <PersonFirstNm>First Name Person</PersonFirstNm>
//  <PersonLastNm>Last Name Person</PersonLastNm>
//</ContactNameGrp> <ContactPhoneNum>9090909000</ContactPhoneNum>
//</root>

创建动态xml文件

1 个答案: