Question

程序必须读取input.txt的内容，找到最小值，最大值和平均值，然后将结果打印到新文件中。

到目前为止，这是我的代码

# to open the txt file in read and write mode
text_file = open('input.txt', 'r+')

# we now create a list for the numbers in the program
number_list = []

# now we create a loop that loops over each line in the txt file
for line in text_file:
    number_list.append(line.split(','))

Answer 1

首先，您想使用with之类的上下文管理器来自动打开和关闭文件

然后，您可以使用python内置min max和sum来分别计算最小值，最大值和平均值

#Open the txt file in read and write mode, and get all integers in file
number_list = []
with open('file.txt', 'r') as fp:
    number_list = [int(item) for item in fp.readlines()]

#Calculate minimum, maximum and average and print it
minimum = min(number_list)
maximum = max(number_list)
average = sum(number_list)/len(number_list)

print('min:', minimum, 'max:', maximum, 'avg:', average)

因此，如果input.txt看起来像这样（每行一个数字）：

输出将为

min: 1 max: 10 avg: 5.5

Answer 2

首先需要将数组转换为int，然后使用max，min和sum，len函数：

number_list_int = [int(i) for i in number_list[0]]

print(min(number_list_int))
print(max(number_list_int))
print(sum(number_list_int)/len(number_list_int))

Answer 3

我假设文件包含用换行符分隔的整数值

>>> # Read file into an array and convert string form integers to int
>>> fd = open("nums")
>>> nums = map(int, fd.read().strip().splitlines())
>>> fd.close()
>>> nums
[12, 15, 5, 89, 2, 3, 5, 6, 11]

>>> # Following functions are self explanatory
>>> max(nums)
89
>>> min(nums)
2
>>> sum(nums)
148
>>> len(nums)
9

>>> # write to file
>>> fd = open("result", "w")
>>> fd.write("max: " + str(max(nums)))
>>> fd.write("\nmin: " + str(min(nums)))
>>> fd.write("\navg: " + str(sum(nums) / len(nums)))
>>> fd.close()

在txt文件中查找列表的最小，最大和平均值

3 个答案: