Question

我在以入队方法显示吐司消息时遇到问题。将值插入数据库时，toast消息不会出现在android屏幕上。我认为无法使用入队方法。

我该如何解决。

private void addValueToDatabase(final String name,final String surname) {
        Log.i(LOG,"addValueToDatabase method is working");
        result = new Result();
        Call<Result> x = Manager.getInstance().addUser(name,surname);
        x.enqueue(new Callback<Result>() {
            @Override
            public void onResponse(Call<Result> call, Response<Result> response) {
                if(response.isSuccessful()){
                    result = response.body();
                    Toast.makeText(getApplicationContext(), result.getResult(), Toast.LENGTH_LONG).show();
                }
            }

            @Override
            public void onFailure(Call<Result> call, Throwable t) {
                Log.i(LOG,"addValueToDatabase error........................");
            }
        });
    }

其余插入过程

@FormUrlEncoded
    @POST("/insert.php")
    Call<Result> addUser(@Field("ad") String ad ,@Field("soyad") String soyad);

insert.php

<?php

        //Getting post data 
        $name = $_POST["ad"];
        $username = $_POST["soyad"];

        //If the values are not blank
        //Connecting to our database by calling dbConnect script 
        include('connection.php');  

        //If username is not already exist 
        //Creating insert query 
        $sql = "INSERT INTO kullanici (ad,soyad) VALUES('$name','$username')";

        //Trying to insert the values to db 
        if(mysqli_query($conn,$sql)){
            //If inserted successfully 
            $x = (array('Result' => "Ekleme Başarılıdır..."));
            echo json_encode($x);
        }else{
            //In case any error occured 
            echo 'oops! Please try again!';
        }

        //Closing the database connection 
        mysqli_close($conn);

?>

Answer 1

您最有可能从后台线程调用数据库代码（以防止冻结前端UI），但是随后您试图从非UI线程显示UI元素（敬酒通知）。要显示Toast消息，请尝试通过UI线程进行操作：

activity.runOnUiThread(new Runnable() {
    public void run() {
        Toast.makeText(getApplicationContext(), result.getResult(), Toast.LENGTH_LONG).show();
    }
});

将值添加到MySql数据库后无法显示吐司消息

1 个答案: