Question

var geocoder = new google.maps.Geocoder();
            geocoder.geocode({'latLng': foundLoc}, function(results, status) {
                if (status == google.maps.GeocoderStatus.OK) {
                    if (results[1]) {
                        var loc = getCityState(results);
                    }
                }
            }); 

function getCityState(results)
        {
            var citystateArray = results[1].formatted_address.split(",",2);
            var city = citystateArray[0];
            var state = citystateArray[1].substring(1, 3);
            return (city + ', ' + state)
        }

这就是我现在使用的，大约90％的时间都可以使用。其他时候，formatted_address包含一个城镇和一个城市以及州，其他时间只有城镇和城市，其他时间你可以梦想的一切。

我还没有找到一种始终如一的方式来获取Google Maps API结果中的城市/州。你们中的任何人都有吗？感谢。

Google在其网页上使用的一个响应示例：

{
  "status": "OK",
  "results": [ {
    "types": [ "street_address" ],
    "formatted_address": "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
    "address_components": [ {
      "long_name": "1600",
      "short_name": "1600",
      "types": [ "street_number" ]
    }, {
      "long_name": "Amphitheatre Pkwy",
      "short_name": "Amphitheatre Pkwy",
      "types": [ "route" ]
    }, {
      "long_name": "Mountain View",
      "short_name": "Mountain View",
      "types": [ "locality", "political" ]
    }, {
      "long_name": "California",
      "short_name": "CA",
      "types": [ "administrative_area_level_1", "political" ]
    }, {
      "long_name": "United States",
      "short_name": "US",
      "types": [ "country", "political" ]
    }, {
      "long_name": "94043",
      "short_name": "94043",
      "types": [ "postal_code" ]
    } ],
    "geometry": {
      "location": {
        "lat": 37.4219720,
        "lng": -122.0841430
      },
      "location_type": "ROOFTOP",
      "viewport": {
        "southwest": {
          "lat": 37.4188244,
          "lng": -122.0872906
        },
        "northeast": {
          "lat": 37.4251196,
          "lng": -122.0809954
        }
      }
    }
  } ]
}

有时这些字段没有值，有时它们也有。

Answer 1

为什么要解析formatted_address？

有address_components，您可以浏览它们并查找

的那些

"types": [ "administrative_area_level_1", "political" ]// the state
"types" : [ "locality", "political" ]//the city

以下是一个示例：http://jsfiddle.net/doktormolle/QWPCL/

Answer 2

到目前为止，这似乎对我有用......

  readCityAndStateFromResult: (data) ->
    displayName = []
    for component in data[0].address_components
      if component.types and component.types.length
        switch true
          when 'locality' in component.types
            displayName.push component.long_name
          when 'administrative_area_level_1' in component.types or 'administrative_area_level_2' in component.types
            displayName.push component.short_name
    return displayName.join ', ' if displayName.length
    return null

从Google地图请求中解析城市/州

2 个答案: