如何插入选定的单选按钮?

时间:2012-04-08 23:48:15

标签: php javascript jquery

我有一个jsfiddle here。如果您选择一个单选按钮并单击“添加问题”,它将添加一个表格行,显示您选择的单选按钮。您可以更改行中的选择。

现在我想做的是我想使用INSERT VALUES方法在数据库中的每个按钮中插入所选的单选按钮。

所以我想知道的是我如何才能正确地执行此操作,以便$ _POST每行的选定单选按钮,然后能够使用INSERT VALUES插入它们?

下面是我目前拥有的PHP代码:('questionText'是'问题'列,它实际上挑选了每一行,即使我没有在jsfiddle中包含'questionText'并且'gridValues'不在jsfiddle,但是对于'Options'列中每行的每个文本框值,所以想象一下表中还有两列是'Question'和'Options'列。)

$i = 0;
$c = count($_POST['gridValues']);

$insertquestion = array();

for($i = 0;  $i < $c; $i++ ){

    switch ($_POST['gridValues'][$i]){

    case "3": 
    $selected_option = "A-C";
    break;

    case "4": 
    $selected_option = "A-D";
    break;

    default:
    $selected_option = "";
    break;

    }     

    foreach($_POST['reply'] as $reply) {

     switch ($_POST['reply']){

    case "Single": 
    $selected_reply = "Single";
    break;

    case "Multiple": 
    $selected_reply = "Multiple";
    break;

    default:
    $selected_reply = "";
    break;    
}
} 

    $optionquery = "SELECT OptionId FROM Option_Table WHERE (OptionType = '". mysql_real_escape_string($selected_option)."')";
    $optionrs = mysql_query($optionquery);
    $optionrecord = mysql_fetch_array($optionrs);
    $optionid = $optionrecord['OptionId'];  

    $replyquery = "SELECT ReplyId FROM Reply WHERE (ReplyType = '". mysql_real_escape_string($selected_reply)."')";
    $replyrs = mysql_query($replyquery);
    $replyrecord = mysql_fetch_array($replyrs);
    $replyid = $replyrecord['ReplyId'];   

    $insertquestion[] = "'".  
                    mysql_real_escape_string( $_POST['questionText'][$i] ) ."','".  
                    mysql_real_escape_string( $optionid ) ."','".  
                    mysql_real_escape_string( $replyid ) ."'";

}

 $questionsql = "INSERT INTO Question (QuestionContent OptionId, ReplyId) 
    VALUES (" . implode('), (', $insertquestion) . ")";

echo($questionsql);

1 个答案:

答案 0 :(得分:2)

我注意到你的jsfiddle中每个新创建的单选框都被创建为reply1和reply2。

但是在你的php代码中,它看起来像是一个循环,好像它是一个数组。

如果您对帖子值执行print_r,则会得到类似

的内容
Array ( [reply1] => Single [reply2] => Multiple )     

所以它们不是数组格式。如果POST请求中的唯一值是单选按钮,则可以循环POST数组值。

无论如何,这里有一个可能的解决方案,让你循环你的帖子请求。我只是根据你在jsfiddle的例子。您可能必须适应您的实际代码。但他们的关键是要注意,单选按钮的名称被命名为reply[0]reply[1]。 PHP知道将名称中的值命名为数组。

<?php

//This is what your values will look like. Notice that they are in array format now
print_r($_POST);

foreach($_POST['reply'] as $reply) {
    //Now you can loop through your replies correctly.
}

?>

<!-- Quick Example of how to name the radio buttons -->
<html>
<head></head>
<body>
<form method="post">
Row 1<br />
<input type="radio" value="Single" name="reply[0]" /> Single 
<input type="radio" value="Multiple" name="reply[0]" /> Multiple

<br />Row 2<br />
<input type="radio" value="Single" name="reply[1]" /> Single 
<input type="radio" value="Multiple" name="reply[1]" /> Multiple
<br />
<input type="submit" value="Submit" />
</form>
</body>


以上代码仅针对回复重写。由于我不确定数据是如何格式化或数据实际存在的,因此我将其他内容留下了。我想知道为什么你不只是使用id为收音机盒值而不是文本。这样您就不必继续查询数据库了。您可以只查询所有回复类型,然后匹配id。

<?php

$insertquestion = array();

foreach($_POST['reply'] as $reply) {

    switch ($reply){

    case "Single": 
    $selected_reply = "Single";
    break;

    case "Multiple": 
    $selected_reply = "Multiple";
    break;

    default:
    $selected_reply = "";
    break;

    $replyquery = "SELECT ReplyId FROM Reply WHERE (ReplyType = '". mysql_real_escape_string($selected_reply)."')";
    $replyrs = mysql_query($replyquery);
    $replyrecord = mysql_fetch_array($replyrs);
    $insertquestion[] = $replyrecord['ReplyId'];       
}

$questionsql = "INSERT INTO Question (ReplyId) 
    VALUES (" . implode('), (', $insertquestion) . ")";

echo($questionsql);

除了使用for循环之外,这里基本相同。我猜你不熟悉foreach循环。但在这种情况下,for循环也可以为你提供更好的服务。

<?php

$insertquestion = array();

for($i = 0; $i < count($_POST['reply']), $i++) {

    switch ($_POST['reply'][$i]){

    case "Single": 
    $selected_reply = "Single";
    break;

    case "Multiple": 
    $selected_reply = "Multiple";
    break;

    default:
    $selected_reply = "";
    break;

    $replyquery = "SELECT ReplyId FROM Reply WHERE (ReplyType = '". mysql_real_escape_string($selected_reply)."')";
    $replyrs = mysql_query($replyquery);
    $replyrecord = mysql_fetch_array($replyrs);
    $insertquestion[] = $replyrecord['ReplyId'];       
}

$questionsql = "INSERT INTO Question (ReplyId) 
    VALUES (" . implode('), (', $insertquestion) . ")";

echo($questionsql);