Android:在多选对话框中跟踪已检查的值

时间:2012-04-09 04:20:26

标签: android dialog multi-select

我有一个按钮,点击该按钮我会显示一个多选对话框。我使用数据库中的值加载对话框。我想跟踪对话框中检查的值。我怎么做??在最初加载对话框时是否可以检查一些服务。 我的ButtonOnClickHandler代码如下:

class ButtonClickHandler implements View.OnClickListener {      
    public void onClick( View view ) {  
        int i=0;  
        List<Service> svc = EditBusinessdh.getServiceList();  
        Log.v(TAG, "Setting svc size:"+ svc.size()  );  
        serName = new ArrayList<String>();  
        for(i=0;i<svc.size();i++)  
        {  
        serName.add(svc.get(i).toString());                 
        Log.v(TAG, "service ="+svc.get(i));  
        }  
        showDialog(0);  
    }  
}  

@Override  
protected Dialog onCreateDialog(int id)   
{  
String[] ser =  serName.toString().substring(1,serName.toString().length()-1).split(",");  
return new AlertDialog.Builder( this )  
    .setTitle( "Select Services" )  
    .setMultiChoiceItems(ser, selected, new DialogSelectionClickHandler())  
    .setPositiveButton( "Ok", new DialogButtonClickHandler() )  
    .create();  
}  

public class DialogSelectionClickHandler implements DialogInterface.OnMultiChoiceClickListener  
{  
public void onClick( DialogInterface dialog, int clicked, boolean checked )  
{  
    String firstSelected= serName.set(clicked, ser.toString());  
}  
}  


public class DialogButtonClickHandler implements DialogInterface.OnClickListener  
{  
    public void onClick( DialogInterface dialog, int clicked )  
    {  
    switch( clicked )  
    {  
        case DialogInterface.BUTTON_POSITIVE:  
            closeContextMenu();  
            break;  

        case DialogInterface.BUTTON_NEGATIVE:  
            break;  
    }  
    }  
}  

@Override  
public void closeContextMenu() {  
    super.closeContextMenu();       
}  

谢谢

1 个答案:

答案 0 :(得分:2)

创建一个ArrayList,在选择选项时只需添加到列表中,同时取消选择将其从列表中删除。多数民众赞成

ArrayList<String> checkedValue= new ArrayList<String>();


public void onClick( DialogInterface dialog, int clicked, boolean checked )  
{  
      if (isChecked) 
            {
                if(!checkedValue.contains(ser[which]))
                    checkedValue.add(ser[which]);
            } 
            else
            {
              if(checkedValue.contains(ser[which]))
                  checkedValue.remove(ser[which]);
            }

}