jqm将选择菜单更改为基本列表?

时间:2012-04-11 11:22:36

标签: php list jquery-mobile

这可能非常简单,但我不习惯这种编码方式 - 如何更改此选择菜单:

$control .= '<select name="'. $this->_hash_value($hash, $xml_obj->value) .'" id="'. $this->_hash_value($hash, $xml_obj->value) .'" data-native-menu="false">';
foreach ($nameArr as $folder => $imageArr) {
            foreach ($imageArr as $image) {
                if (substr($folder, 1, strlen($folder)).$image == $xml_obj->value) {
                    $control .= '<option value="'. substr($folder, 1, strlen($folder)).$image .'" selected="selected">'. $image .'</option>';
                } else {
                    $control .= '<option value="'. substr($folder, 1, strlen($folder)).$image .'">'. $image .'</option>';
                }
            }
        }
        $control .= '</select>';

进入单个列表项(具有当前所选项的值),该列表项会导致基本列表包含用户可以选择的所有项目?

2 个答案:

答案 0 :(得分:1)

你应该可以这样做:

$control .= '<ul id="'. $this->_hash_value($hash, $xml_obj->value) .'" data-role="listview" data-theme="g">';
foreach($nameArr as $folder => $imageArr)
{
   foreach ($imageArr as $image) {
      $control .= '<li><a href="'. substr($folder, 1, strlen($folder)).$image .'">'. $image .'</a></li>';
   }
}
$control .= "</ul>";

答案 1 :(得分:0)

清单1:

$control .= '<ul data-role="listview" data-inset="true">';
        $control .= '<li>';
        $control .= '<a href="'. site_url() .'/mobilegallery/gallery/'.$x[0]->attributes()->indexI.'">Bilder</a>';
        $control .= '</li>';
        $control .= '</ul>';

列表2,在新页面上:

$html .= '<ul data-role="listview" class="ui-listview" data-inset="true">';
    for($i = 0, $c = $xml->COM->MOVIE->count(); $i < $c; $i++ ){

        $html .= '<li>';
        $html .= '<a>
        <img src="https://[url]/'.rawurlencode($this->_decode_path($xml->COM->MOVIE[$i]->attributes()->dbIcoFilename)).'" id="imgThumb" alt="'.$xml->COM->MOVIE[$i]->attributes()->nameS.'" />
        <h1>'.$xml->COM->MOVIE[$i]->attributes()->nameS.'</h1>
        </a>';
        $html .= ' </li>';

    }
    $html .= '</ul>';
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