如何提高分数'在快速枚举期间

时间:2012-04-16 20:24:06

标签: cocoa increment fast-enumeration

我有以下代码,我想用它来检查用户答案并输出分数(满分5分)。我使用带有答案的plist并检查textField.text。我正在努力的是:如何使用这种方法获得总分输出分数?

- (IBAction)checkAnswers:(UITextField *)textField
{
NSString *path2 = [[NSBundle mainBundle] pathForResource:@"7A Cells Microscopes 3" ofType:@"plist"];
NSDictionary *dictionary = [[NSDictionary alloc] initWithContentsOfFile:path2];

NSString *tester = [NSString stringWithFormat:@"%i", textField.tag];

//   NSDictionary *secondDict = [dictionary valueForKey:tester];

//  NSString *answer = [secondDict valueForKey:@"Answer"];

// if ([textField.text isEqualToString:[[dictionary valueForKey:tester] valueForKey:@"Answer"]]) {
//      NSLog(@"YAY");
//  }

NSArray *allTextFields = [[NSArray alloc] initWithObjects:eyepiece, objectiveLens, focussingKnobs, stage, mirror, nil];


for (textField in allTextFields) {
                int x = 0;

    if ([textField.text isEqualToString:[[dictionary valueForKey:tester] valueForKey:@"Answer"]]) {
        x++;
        NSLog(@"%i", x);
    }

}

任何帮助将不胜感激! 非常感谢。

1 个答案:

答案 0 :(得分:3)

假设您的其余代码都很好,只需在for循环外移动 int x = 0; 。你编码x的方式在每个循环中重置为0 ......所以它永远不会计数。