Question

[已解决：感谢bluefeet和Brian我必须构建这个工作查询（原来我还需要第四张表/视图）]“

SELECT        A.SalesLineID, A.ArticleResultID, B.ID, C.ID, D.Value
FROM            VIEWA AS A 
                INNER JOIN TABLEB AS B ON A.ArticleResultID = B.ArticleResultID 
                AND B.Name = N'Collect' AND DAPR.Value = 1 
                INNER JOIN TABLEC AS C ON B.ArticleResultID = C.ID 
                AND C.Name='Assemble' 
                AND C.Value = 1 
                INNER JOIN TABLED AS D ON D.ArticleResultID = C.ParentId 
                AND D.Name = 'IndexY'
WHERE        (A.SalesID = @SalesID)

[更新：假设IndexY / Color和ProdId我犯了一个错误，其中字段表A是某种参数/属性表，只有5列ID - NAME - VALUE - ARTICLERESULTID - PRODID。 IndexY是Name字段的值..]

我无法构建正确的sql查询来完成这个技巧：

我有以下2个表格：

Table A 
ID Name         Value   ArticleResultID     ProdID    Color
1  Operation    Collect             110         10    BLACK
2  IndexY            10             110         10    - 
3  Operation    Collect             101         11    WHITE


Table B
ID  ParentID    Name        Value       
101 110     Assemble        1       
101 100     Assemble        0

步骤：

Find record in A with Name = Operation and Value = Collect and ProdId = 11 AS ORG_A
Find record in B With B.ID = ORG_A.ArticleResultId AND B.NAME = 'Assemble'AND B.VALUE = 1 AS B
Find record in A With A.ArticleResultID = B.ParentID as NEW_A

在上面的场景中，ORG_A.ArticleResultID = 11 - ＆gt; B.ParentID = 110 - ＆gt; NEW_A.ARTICLERESULTID = 110 - ＆gt; （IndexY - Value - 10）

非常感谢，如果有人可以告诉我如何构建此查询..

致以最诚挚的问候，

Mike D

[OLD DESCRIPTION：]

我无法构建正确的sql查询来完成这个技巧：

我有以下2个表格：

Table A 
Name        Value   ArticleResultID      IndexY      Color  ProdID
Operation   Collect             110         10           -       0
Operation   Collect             101         _        Black     100  


Table B
ID  ParentID    Name        Value   Dx      Dy
101 110     Assemble        1       1000    500 
101 100     Assemble        0       400     300

我想从A中获取所有记录，其中NAME等于'operation'，VALUE等于'Collect'和PRODID ='100'但我也希望（这是我的问题）表A中记录的IndexY值与PARENTID在表B中加入表B.ID = A.ArticleResultID AND Name ='Assemble'和VALUE ='1'

在上面的场景中，ParentID 110给了我表A中的记录，其中ArticleResultID 110带有IndexY（10）。

非常感谢，如果有人可以告诉我如何构建此查询..

致以最诚挚的问候，

Mike D

Answer 1

这对你有用吗？

SELECT a.*,c.IndexY
  FROM [TableA] a
  JOIN [TableB] b ON a.ArticleResultId = b.id
                 AND b.Name ='Assemble'
                 AND b.Value = 1
  JOIN [TableA] c ON b.ParentId = c.ArticleResultID
  WHERE a.name = 'Operation'
    AND a.Value = 'Collect'
    AND a.ProdId = 100

Answer 2

因为您的要求不是最清楚的。怎么样：

SELECT a1.*, a2.indexy as additionalIndexY
FROM ta a1
INNER JOIN tb b
    ON a1.articleresultid = b.id
INNER JOIN ta a2
    ON b.parentid = a2.articleresultid
WHERE a1.name = 'Operation'
    AND a1.prodid = 100
    AND b.name = 'Assemble'
    AND b.value = 1

这是一个sqlfiddle，其工作版本

如果您只想要110 articlereulti的记录，那么：

SELECT a2.*
FROM ta a1
INNER JOIN tb b
    ON a1.articleresultid = b.id
INNER JOIN join ta a2
    ON b.parentid = a2.articleresultid
WHERE a1.name = 'Operation'
    AND a1.prodid = 100
    AND b.name = 'Assemble'
    AND b.value = 1

请参阅sqlfiddle获取第二个示例

SQL查询获取基于parentid表B的记录表A.

2 个答案: