Question

我正在尝试创建一个程序（将一个新的类名，类型，国家，枪支数量，钻孔和位移作为参数。将此信息添加到类中，并将带有类名的船添加到船上）

关系：

classes(class, type, country, numGuns, bore, displacement)
ships(name, class, launched)


mysql> CREATE PROCEDURE addClass(in VARCHAR(50) inClassName, in VARCHAR(5) inType, in
VARCHAR(50) inCountry, in INT inNumGuns, in INT inBore, in INT inDis)
-> begin
-> INSERT INTO classes VALUES(inClassName, inType, inCountry, inNumGuns, inBore, inDis);
-> INSERT INTO ships VALUES(inClassName, inClassName, NULL);
-> end
-> //
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near 'VARCHAR(50)
inClassName, in VARCHAR(50) inType, in VARCHAR(50) inCountry, in INT' at line 1

我不确定这个错误的来源，有人可以帮忙吗？

Answer 1

输入变量名称在它们的数据类型之前，而不是在您指定它们之后：

CREATE PROCEDURE addClass(
  in inClassName VARCHAR(50),
  in inType VARCHAR(5) , 
  in inCountry VARCHAR(50), 
  in inNumGuns INT,
  in inBore INT,
  in inDis INT
)
BEGIN
  INSERT INTO classes VALUES(inClassName, inType, inCountry, inNumGuns, inBore, inDis);
  INSERT INTO ships VALUES(inClassName, inClassName, NULL);
END

From the CREATE PROCEDURE docs，规范看起来像

proc_parameter:
    [ IN | OUT | INOUT ] param_name type

Answer 2

更正语法。这是一个例子：

delimiter //

CREATE PROCEDURE addClass(in inClassName VARCHAR(50),
in inType VARCHAR(5), in inCountry VARCHAR(50),
in inNumGuns INT, in inBore INT, in inDis INT)

begin

INSERT INTO classes VALUES(inClassName, inType, inCountry, inNumGuns, inBore, inDis);
INSERT INTO ships VALUES(inClassName, inClassName, NULL);

end//

delimiter ;

MySQL无法创建程序

2 个答案: