我的CSV文件包含---
等数据filename, title, docType "abc.pdf","DesignDocument1", "design" "125_df.pdf","testingDocument", "Test" "abc4.pdf","","design"
我想用PHP来:---
我正在寻找像
这样的表输出fileID filename, title, doctype 00001 abc.pdf DesignDocument1 design 00002 125_df.pdf testingDecument Test 00003 abc4.pdf design
我将非常感谢任何有效实施这些建议/程序的建议/程序
我为我糟糕的英语道歉
答案 0 :(得分:0)
使用LOAD DATA INFILE:
LOAD DATA INFILE 'yourfilename.txt' INTO TABLE yourtablename (col1,col2,...);
在PHP中,您将运行与此类似的查询:
mysql_query("LOAD DATA INFILE 'yourfilename.txt' INTO TABLE `yourtablename` FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n';",$con)