Question

每一个人，我都面临小问题，希望任何人都能帮助我。这是电子购物网站，我只是想要一些帮助。按下添加到购物车链接后的想法将它转移到购物车页面，有两个链接编辑和删除，删除将删除该项目，这是工作。但是当有人按下编辑链接时，数量栏中的文本框会出现，一旦按下保存，也会出现保存链接，数据库中会有更新

问题是：1-如何将文本框值从案例“showupdate”转移到另一个案例“savee”？我试过$qq=$_POST['qun'];并在动作和id旁边的save链接中发送变量，但是它总是起作用总是说未定义的变量'qun'

第二个问题是：文本框和保存链接出现在购物车上的所有项目中，我不希望这样，我只想按下它旁边的那个项目，更改为文本框并保存链接。< / p>

我知道我已经把while循环，这只是为了确保当按下链接编辑时，项目的ID得到它只有谁将获得文本框并保存链接

这里是代码请帮帮我，

switch($action){
case "add":
{$id=$_REQUEST['id'];
 $query='insert into cart values("1",'.$id.',"1")';
 $result=mysql_query($query);
 header("location:cart.php?action=show");
    break;
}
case "remove":
{ $id=$_REQUEST['id'];
echo $id;
$query='delete from cart where itemId='.$id.'' or die(mysql_error());
$result = mysql_query($query) or die(mysql_error());
header ("location:cart.php?action=show");
break;}


    case "showupdate":
    { $id=$_REQUEST['id'];
      $sql2="select * from cart";
      $result2= mysql_query($sql2);
      while($row2 = mysql_fetch_array($result2))
    {   if ( $id == $row2['itemId'])
        {   $totalCost =0;
            $query = "select * from cart inner join items on cart.itemId = items.itemId";
            $result = mysql_query($query);
            ?>
            <table width="100%" border="1"> 
            <?php while($row = mysql_fetch_array($result)){
            $totalCost += ($row["qty"] * $row["itemPrice"]);
            ?>
            <tr>
            <td><img src="<?php echo $row["image"];?>" height="50" width="50"/></td>
            <td><?php echo $row["itemName"]; ?></td>
            <td>SR<?php echo $row["itemPrice"]; ?></td>
            <td>
            <form method="POST" name="form1">
            <input type = "text" name="qun" value="<?php echo $row['qty'];?>" size="10"/> 
            </form>
            </td>
            <td><a href="cart.php?action=savee&id=<?php echo $row["itemId"]; ?>">Save</a></td>
            <td><a href="cart.php?action=remove&id=<?php echo $row["itemId"]; ?>">Remove</a></td>
            </tr>
            <?php } 

           // Increment the total cost of all items
           $totalCost += ($row["qty"] * $row["itemPrice"]);
           $totalCost = $totalCost + ($row["qty"] * $row["itemPrice"]); ?>
           <tr> <td colspan="2"> <a href="homestore.php">Keep Shopping</a></td>
           <td colspan="2"> <b>Total: SR<?php echo $totalCost; ?></b></td></tr>
           </table>
           <?php  } 
        } break;}


    case "savee":
    {  $id=$_REQUEST['id'];
       $sql='update cart set qty='.$_POST['qun'].'where itemId='.$id.''or die(mysql_error());
       $result=mysql_query($sql)or die(mysql_error());
        header ("location:cart.php?action=show");
        break;
    }

    case "show":
    {
    $totalCost =0;
    $query = "select * from cart inner join items on cart.itemId = items.itemId";
    $result = mysql_query($query);
    ?>
    <table width="100%" border="1"> 
        <?php while($row = mysql_fetch_array($result))
        {   
        $totalCost += ($row["qty"] * $row["itemPrice"]);
        ?>
        <tr>
        <td><img src="<?php echo $row["image"];?>" height="50" width="50"/></td>
        <td><?php echo $row["itemName"]; ?></td>
        <td>SR<?php echo $row["itemPrice"]; ?></td>
        <td><a href="cart.php?action=showupdate&id=<?php echo $row["itemId"]; ?>">edit</a></td>
        <td><a href="cart.php?action=remove&id=<?php echo $row["itemId"]; ?>">Remove</a></td>
       </tr>
    <?php } 

    // Increment the total cost of all items
    $totalCost += ($row["qty"] * $row["itemPrice"]);
    $totalCost = $totalCost + ($row["qty"] * $row["itemPrice"]); ?>
    <tr> <td colspan="2"> <a href="homestore.php">Keep Shopping</a></td>
    <td colspan="2"> <b>Total: SR<?php echo $totalCost; ?></b></td></tr>
    </table>

    <?php break; }
    }?>

如果我点击添加链接，它将转移action =“add”和该项目的ID 之后它将插入到开关状态添加案例因为有标题（“位置..”）它将立即转移以显示案例，向我们显示表编辑+删除链接一旦点击编辑链接它将进入showupdate案例显示文本框+保存链接一旦单击保存它将转到保存案例。

Answer 1

一个。要始终使用$_POST['qun']将其保存在会话中，请参阅http://php.net/manual/en/function.session-start.php了解文档

示例

session_start();
$_SESSION['qun'] = $_POST['qun'] ;


// to get qun back
echo $_SESSION['qun'] ;

B中。你的代码充满了SQL注入尝试使用mysql_real_escape_string来发布所有发布的数据

 $id = mysql_real_escape_string ( $_POST ['id'] );

℃。抱歉，我可以为您编写整个class，但这是一个示例，说明您的代码看起来如何干净

include 'runner.class.php';
$runner = new Runner ( $action );
$runner->process ();

// runner.class.php

class Runner {
    private $action;
    private $id;
    private $qun;
    function __construct($action) {
        $this->action = $action;
        $this->id = mysql_real_escape_string ( $_REQUEST ['id'] );
        $this->qun = mysql_real_escape_string ( $_REQUEST ['id'] );

    }

    function process() {
        switch ($this->action) {
            case "add" :
                $this->add ();
                break;

            case "remove" :
                $this->remove ();
                break;

            case "savee" :
                $this->save ();
                break;
            case "show" :
                $this->show ();
                break;

        }
    }
    function add() {
        $query = 'insert into cart values("1",' . $this->id . ',"1")';
        $result = mysql_query ( $query );
        header ( "Location: cart.php?action=show" );
    }

    function remove() {
        $query = 'delete from cart where itemId=' . $this->id . '' or die ( mysql_error () );
        $result = mysql_query ( $query ) or die ( mysql_error () );
        header ( "Location: cart.php?action=show" );
    }

    function save() {
        $_SESSION ['qun'] = mysql_real_escape_string ( $_POST ['qun'] ); // Save
                                                                         // Quu
        $sql = 'update cart set qty=' . $_POST ['qun'] . 'where itemId=' . $this->id . '' or die ( mysql_error () );
        $result = mysql_query ( $sql ) or die ( mysql_error () );
        header ( "Location: cart.php?action=show" );
        break;
    }

    function showUpdate() {
        $_SESSION ['qun'] = mysql_real_escape_string ( $_POST ['qun'] ); // Save Quu
        // Add Code
    }

    function show() {
        $qun = $_SESSION ['qun']; // Use Qui
         // Add Code
    }

}

如何在switch中传输2个案例之间的文本框值

1 个答案: