我搜索过PHP手册，Stackoverflow和一些论坛，但我对一些PHP逻辑感到难过。也许我只是累了，但我真的很感激任何人的帮助或指导。
我有一个PHP字符串，比如说：
$string = 'cats cat1 cat2 cat3 dogs dog1 dog2 monkey creatures monkey_creature1 monkey_creature2 monkey_creature3';
最终，我希望我的最终输出看起来像这样，但是现在只需要获取数组就可以了：
<h2>cats</h2>
<ul>
<li>cat1</li>
<li>cat2</li>
<li>cat3</li>
</ul>
<h2>dogs</h2>
<ul>
<li>dog1</li>
<li>dog2</li>
</ul>
<h2>monkey creatures</h2>
<ul>
<li>monkey_creature1</li>
<li>monkey_creature2</li>
<li>monkey_creature3</li>
</ul>
虽然有一个问题，但有时字符串会略有不同：
$string = 'cats cat1 cat2 cat3 cat4 cat5 cats6 dogs dogs1 dogs2 monkey creatures monkey_creature1 lemurs lemur1 lemur2 lemur3';
无论如何，这是我在Stackoverflow上的第一个问题，并提前感谢所有帮助人员！
编辑：我正在某些限制下工作，我无法在字符串之前更改任何代码。我知道所有的父母（'猫'，'狗'，'狐猴'，'猴子生物（有空间）'
答案 0 :(得分：4)
我设计的答案无论“关键字”之间是否有空格都有效，只要第一个关键字不是复数：）
下面是代码，随便查看一下，你用文字做什么真的很漂亮:)。
<?
$string = 'cats cat1 cat2 cat3 dogs dog1 dog2 monkey creatures monkey_creature1 monkey_creature2 monkey_creature3';
$current_prefix = '';
$potential_prefix_elements = array();
$word_mapping = array();
foreach(split(" ", $string) as $substring) {
if(strlen($current_prefix)) {
// Check to see if the current substring, starts with the prefix
if(strrpos($substring, $current_prefix) === 0)
$word_mapping[$current_prefix . 's'][] = $substring;
else
$current_prefix = '';
}
if(!strlen($current_prefix)) {
if(preg_match("/(?P<new_prefix>.+)s$/", $substring, $matches)) {
$potential_prefix_elements[] = $matches['new_prefix'];
// Add an 's' to make the keys plural
$current_prefix = join("_", $potential_prefix_elements);
// Initialize an array for the current word mapping
$word_mapping[$current_prefix . 's'] = array();
// Clear the potential prefix elements
$potential_prefix_elements = array();
} else {
$potential_prefix_elements[] = $substring;
}
}
}
print_r($word_mapping);
这是输出，我已经将它作为数组提供给您，因此您可以轻松构建ul / li层次结构：）
Array
(
[cats] => Array
(
[0] => cat1
[1] => cat2
[2] => cat3
)
[dogs] => Array
(
[0] => dog1
[1] => dog2
)
[monkey_creatures] => Array
(
[0] => monkey_creature1
[1] => monkey_creature2
[2] => monkey_creature3
)
)
答案 1 :(得分：2)
您可能希望使用preg_match_all函数并使用正则表达式。这样，您就不必使用任何循环：
$matches = array();
$string = 'cats cat1 cat2 cat3 dogs dog1 dog2 monkey creatures monkey_creature1 monkey_creature2 monkey_creature3'
preg_match_all('/((?:[a-z]+ )*?[a-z]+s) ((?:[a-z_]+[0-9] ?)+)*/i', $string, $matches);
// $matches now contains multidemensional array with 3 elements, indices
// 1 and 2 contain the animal name and list of those animals, respectively
$animals = array_combine($matches[1], $matches[2]);
$animals = array_map(function($value) {
return explode(' ', trim($value));
}, $animals);
print_r($animals);
输出：
Array
(
[cats] => Array
(
[0] => cat1
[1] => cat2
[2] => cat3
)
[dogs] => Array
(
[0] => dog1
[1] => dog2
)
[monkey creatures] => Array
(
[0] => monkey_creature1
[1] => monkey_creature2
[2] => monkey_creature3
)
)
答案 2 :(得分：1)
你的第二个例子是字符串：
<?php
$parents = array('cats', 'dogs', 'monkey creatures', 'lemurs');
$result = array();
$dataString = 'cats cat1 cat2 cat3 cat4 cat5 cats6 dogs dogs1 dogs2 monkey creatures monkey_creature1 lemurs lemur1 lemur2 lemur3';
foreach ($parents as $parent) {
// Consider group only if it is present in the data string
if (strpos($dataString, $parent) !== false) {
$result[$parent] = array();
}
}
$parts = explode(' ', $dataString);
foreach (array_keys($result) as $group) {
$normalizedGroup = str_replace(' ', '_', $group);
foreach ($parts as $part) {
if (preg_match("/^$normalizedGroup?\d+$/", $part)) {
$result[$group][] = $part;
}
}
}
print_r($result);
输出：
Array
(
[cats] => Array
(
[0] => cat1
[1] => cat2
[2] => cat3
[3] => cat4
[4] => cat5
[5] => cats6
)
[dogs] => Array
(
[0] => dogs1
[1] => dogs2
)
[monkey creatures] => Array
(
[0] => monkey_creature1
)
[lemurs] => Array
(
[0] => lemur1
[1] => lemur2
[2] => lemur3
)
)
答案 3 :(得分：1)
这是我的$ 0.50
<?php
$parents = array('cats', 'dogs', 'lemurs', 'monkey creatures');
// Convert all spaces to underscores in parents
$cleaned_parents = array();
foreach ($parents as $parent)
{
$cleaned_parents[] = str_replace(' ', '_', $parent);
}
$input = 'cats cat1 cat2 cat3 dogs dog1 dog2 monkey creatures monkey_creature1 monkey_creature2 monkey_creature3';
// Change all parents to the "cleaned" versions with underscores
$input = str_replace($parents, $cleaned_parents, $input);
// Make an array of all tokens in the input string
$tokens = explode(' ', $input);
$result = array();
// Loop through all the tokens
$currentParent = null; // Keep track of current parent
foreach ($tokens as $token)
{
// Is this a parent?
if (in_array($token, $cleaned_parents))
{
// Create the parent in the $result array
$currentParent = $token;
$result[$currentParent] = array();
}
elseif ($currentParent != null)
{
// Add as child to the current parent
$result[$currentParent][] = $token;
}
}
print_r($result);
输出：
Array
(
[cats] => Array
(
[0] => cat1
[1] => cat2
[2] => cat3
)
[dogs] => Array
(
[0] => dog1
[1] => dog2
)
[monkey_creatures] => Array
(
[0] => monkey_creature1
[1] => monkey_creature2
[2] => monkey_creature3
)
)
答案 4 :(得分：1)
想想我将无法提交最佳答案，因此决定以最少的线路运行。 （开玩笑，抱歉极其肮脏的代码）
$string = 'cats cat1 cat2 cat3 cat4 cat5 cats6 dogs dogs1 dogs2 monkey creatures monkey_creature1 lemurs lemur1 lemur2 lemur3';
$categories = array( 'cats', 'dogs', 'monkey creatures', 'lemurs' );
for( $i=0; $i<count( $categories ); $i++ ) $parts[] = @explode( ' ', strstr( $string, $categories[$i] ) );
for( $i=0; $i<count( $parts ); $i++ ) $groups[] = ($i<count($parts)-1) ? array_diff( $parts[$i], $parts[$i+1] ) : $parts[$i];
for( $i=0; $i<count( $groups ); $i++ ) for( $j=0; $j<count( $groups[$i] ); $j++ ) if( ! is_numeric( substr( $groups[$i][$j], -1 ) ) ) unset($groups[$i][$j]);
print_r( $groups );
您可能会注意到我的方法取决于元素应该具有数字后缀的事实。这实际上是无稽之谈，但我们正在处理的是输入。
我的输出是：
Array
(
[0] => Array
(
[1] => cat1
[2] => cat2
[3] => cat3
[4] => cat4
[5] => cat5
[6] => cats6
)
[1] => Array
(
[1] => dogs1
[2] => dogs2
)
[2] => Array
(
[2] => monkey_creature1
)
[3] => Array
(
[1] => lemur1
[2] => lemur2
[3] => lemur3
)
)