Question

我需要一些帮助来从几个表中获取数据。

这是我的表格：

_______________   ______________   ___________  _______________  _____________
|_tblUsers____|   |_tblAnswers__|  |_tblAlt__|  |_tblQuestion_|  |_survey_____|
| userID      |   | answerAltID |  | altID   |  | questID     |  | surveyID   |
| username    |   | userID      |  | altText |  | questText   |  | surveyName |
|_____________|   |_____________|  |_questID_|  |_surveyID____|  |____________|

TblUsers拥有系统中的用户列表，tblAnswers拥有用户提供的所有答案，tlbAlt拥有问题的替代方案，而tblQuestion有问题。还有一个名为tblSurveys的表，但这里不需要，因为在tblQuestion中提到了ID。

这是我到目前为止所做的：

SELECT
tblQuestion.questText,
tblAlt.altText,
Count(tblAnswers.answerID) as answers_count,
(SELECT COUNT(answerID) FROM tblAnswers, tblAlt 
WHERE tblAnswers.answerAltID = tblAlt.altID 
AND tblAlt.questID = " & CInt(questionID) & ") as total_count
FROM tblAlt, tblQuestion
LEFT JOIN tblAnswers ON (tblAlt.altId = tblAnswers.altID)
WHERE tblAlt.questID = " & CInt(questionID) & "
GROUP BY tblAlt.altText;

这将返回如下行：

|什么是blablabla？ |答案是...... | 2（已回答）| 10（总计答案）|

遗憾的是，这只返回一个问题的所有行。有没有办法让所有行成为同一调查的一部分（基于surveyID）？

如果想要输出如下：

|什么是blablabla？ |答案是...... | 2（已回答）| 10（总计答案）|调查名称|

我想要返回所有替代方案（有多少答案，总答案，相关问题和调查）。

更新

这是我的意见：

SELECT tblalternativ.altTekst, tblalternativ.altID, Count(tblsvar.svarAltID) as antSvar, 
(SELECT COUNT(*) FROM tblsvar, tblalternativ 
WHERE tblsvar.svarAltID = tblalternativ.altID 
AND tblalternativ.altSpmID = " & CInt(lblQuestion.Tag) & ") as antTotal, 
(SELECT Count(*) FROM tblalternativ WHERE altSpmID = " & CInt(lblQuestion.Tag) & ") as spmTotal 
FROM(tblalternativ) LEFT JOIN tblsvar ON (tblalternativ.altId = tblsvar.svarAltID) 
WHERE(tblalternativ.altSpmID = " & CInt(lblQuestion.Tag) & ")
GROUP BY tblalternativ.altTekst ORDER BY tblalternativ.altID ASC

我的输出：

altTekst    altID   antSvar antTotal    spmTotal
Black         83         1      3              5
Green         84         1      3              5
Yellow        85         1      3              5
White         86         0      3              5
Pink          87         0      3              5

但这仅显示一个问题的统计数据。我想在一次调查中显示所有问题。因此，我需要获得该调查的所有altTekst，问题名称和调查ID。

我想：

spmTekst      altTekst  altID   antSvar antTotal    spmTotal   evalID
What is...    Black         83         1        3          5        1
What is...    Green         84         1        3          5        1
What is...    Yellow        85         1        3          5        1
What is...    White         86         0        3          5        1
What is...    Pink          87         0        3          5        1
Who is....    The king      88         2        3          3        1
Who is....    The pope      89         0        3          3        1
Who is....    The president 90         1        3          3        1
Which....     Shoe          91         2        3          2        1
Which....     Hat           92         1        3          2        1

换句话说，我希望同一调查中的所有问题的统计数据（基于evalID）。

Answer 1

返回所有问题，回答文本，使用该答案的用户数以及提供的总答案;每次调查。

Select TQ.QuestText, tAlt.altText, count(*) as Answers_count, suM(mTemp.Cnt) as total_count
FROM tblQuestion tq
LEFT JOIN tblAlt talt on Talt.QuestID = TQ.QuestID
LEFT JOIN tblAnswers ta on ta.AnswerAltID = talt.AltID
LEFT JOIN tblUsers tu ON Ta.UserID = TU.UserID
LEFT join tblAnswers ta2 on ta2.answeraltId = talt.altID
LEFT JOIN 
  (SELECT COUNT(*) cnt, questID 
   FROM tblAnswers 
   INNER JOIN tblAlt on AltID = AnswerAltID
   group by questID) mTemp 
  on mTemp.QuestID = talt.QuestID
WHERE tQ.SurveyID = 123 --Change this to your value
Group by TQ.QuestText, TAlt.AltText

这只是一堆左连接与内连接;并且我抽象出每个表的计数一次，所以它应该更快，而不是在每一行上做一个子选择。通过这种方式，它可以对所有行执行一次并完成。

Answer 2

试试这个（根本没有优化，只是将调查部分添加到其中）：

SELECT    tblQuestion.questText, tblAlt.altText, 
          Count(tblAnswers.answerAltID) AS answers_count,
           (SELECT COUNT(answerAltID) FROM tblAnswers, tblAlt 
           WHERE  tblAnswers.answerAltID = tblAlt.altID AND 
                  tblAlt.questID = " & CInt(questionID) & ") as total_count,
          survey.surveyName
FROM      survey, tblQuestion, tblAlt
LEFT JOIN tblAnswers ON (tblAlt.altId = tblAnswers.answerAltID)
WHERE     tblAlt.questID = " & CInt(questionID) & " AND 
          tblQuestion.surveyID = survey.surveyID
GROUP BY  tblAlt.altText;

编辑：然后尝试：

SELECT    tblQuestion.questText AS spmTekst, tblAlt.altText AS altTekst, 
          tblAlt.altID, 
          Count(tblAnswers.answerAltID) AS antSvar,
          COUNT(tblAlt.altID) AS antTotal,
          COUNT(tblQuestion.questID) AS spmTotal,
          survey.surveyID AS evalID
FROM      tblQuestion 
JOIN      survey ON (survey.surveyID = tblQuestion.surveyID)
JOIN      tblAlt ON (tblAlt.questID = tblQuestion.questID)
LEFT JOIN tblAnswers ON (tblAnswers.answerAltID = tblAlt.altID)
WHERE     tblAlt.questID = " & CInt(questionID) & " AND -- what really is this? review this
          survey.surveyID = '123' -- the value u want
GROUP BY  tblAlt.altText
ORDER BY  tblAnswers.answerAltID;

从数据库中的几个表返回数据

2 个答案: