Question

我刚开始尝试使用Google API。我希望人们能够使用他们的Google登录信息登录我的网站。我已经下载了站点代码及其示例：

<?php
/*
 * Copyright 2011 Google Inc.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
require_once '../src/apiClient.php';
require_once '../src/contrib/apiPlusService.php';

session_start();

$client = new apiClient();
$client->setApplicationName("Google+ PHP Starter Application");
// Visit https://code.google.com/apis/console to generate your
// oauth2_client_id, oauth2_client_secret, and to register your oauth2_redirect_uri.
$client->setClientId('thing here');
$client->setClientSecret('thing here');
$client->setRedirectUri('http://www.pagetworld.co.uk/plustest/index.php');
$client->setDeveloperKey('thing here');
$plus = new apiPlusService($client);

if (isset($_REQUEST['logout'])) {
  unset($_SESSION['access_token']);
}

if (isset($_GET['code'])) {
  $client->authenticate();
  $_SESSION['access_token'] = $client->getAccessToken();
  header('Location: http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF']);
}

if (isset($_SESSION['access_token'])) {
  $client->setAccessToken($_SESSION['access_token']);
}

if ($client->getAccessToken()) {
  $me = $plus->people->get('me');

  // These fields are currently filtered through the PHP sanitize filters.
  // See http://www.php.net/manual/en/filter.filters.sanitize.php
  $url = filter_var($me['url'], FILTER_VALIDATE_URL);
  $img = filter_var($me['image']['url'], FILTER_VALIDATE_URL);
  $name = filter_var($me['displayName'], FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH);
  $personMarkup = "<a rel='me' href='$url'>$name</a><div><img src='$img'></div>";

  $optParams = array('maxResults' => 100);
  $activities = $plus->activities->listActivities('me', 'public', $optParams);
  $activityMarkup = '';
  foreach($activities['items'] as $activity) {
    // These fields are currently filtered through the PHP sanitize filters.
    // See http://www.php.net/manual/en/filter.filters.sanitize.php
    $url = filter_var($activity['url'], FILTER_VALIDATE_URL);
    $title = filter_var($activity['title'], FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH);
    $content = filter_var($activity['object']['content'], FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH);
    $activityMarkup .= "<div class='activity'><a href='$url'>$title</a><div>$content</div></div>";
  }

  // The access token may have been updated lazily.
  $_SESSION['access_token'] = $client->getAccessToken();
} else {
  $authUrl = $client->createAuthUrl();
}
?>
<!doctype html>
<html>
<head>
  <meta charset="utf-8">
  <link rel='stylesheet' href='style.css' />
</head>
<body>
<header><h1>Google+ Sample App</h1></header>
<div class="box">

<?php if(isset($personMarkup)): ?>
<div class="me"><?php print $personMarkup ?></div>
<?php endif ?>

<?php if(isset($activityMarkup)): ?>
<div class="activities">Your Activities: <?php print $activityMarkup ?></div>
<?php endif ?>

<?php
  if(isset($authUrl)) {
    print "<a class='login' href='$authUrl'>Connect Me!</a>";
  } else {
   print "<a class='logout' href='?logout'>Logout</a>";
  }
?>
</div>
</body>
</html>

我测试时效果很好，但如果我尝试以我的妻子（Gmail用户而非Google+用户）身份登录，我的数据就会出现404错误。

此API不适用于普通的Google帐户吗？我应该尝试别的吗？我在他们的网站上找不到一个香草谷歌版本。

使用Google API轻松登录非Google+用户？

0 个答案: