我想迭代所有列来查找和替换特定字符。这是我的pl / sql块:
Declare
match_count Number:=0;
v_search_string VARCHAR2(4000) := '%ي%';
BEGIN
FOR t IN
(SELECT owner,
table_name,
column_name
FROM all_tab_columns
WHERE (SUBSTR(table_name,1,2)='PN'
OR (SUBSTR(table_name,1,2) ='CD'
AND owner ='PNET_USER' ))
AND (data_type ='VARCHAR2'
OR data_type ='CLOB')
)
LOOP
BEGIN
EXECUTE IMMEDIATE 'SELECT count(*) FROM '||t.owner || '.' || t.table_name|| ' WHERE '||t.column_name||' LIKE :1' INTO match_count USING v_search_string;
IF match_count > 0 THEN
dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
--EXECUTE IMMEDIATE 'UPDATE '||t.table_name||' SET '||t.column_name||'=replace()'
END IF;
END;
END LOOP;
它工作正常并打印具有无效字符的列的名称。但我不知道如何更换角色。如何获取t.column_name
的值,替换无效字符,然后更新t.table_name
?
答案 0 :(得分:2)
嗯,这几乎是好的(也是斯特沃的回答)。我让你用你的字符改变v_from和v_to。
Declare
match_count Number :=0;
v_from varchar2(5) := 'a';
v_like varchar2(5) := '%'||v_from||'%';
v_to varchar2(5) := 'b';
v_sql varchar2(1000);
v_emesg varchar2(1000);
CURSOR s is
(SELECT owner, table_name, column_name
FROM all_tab_columns
where SUBSTR(table_name,1,2) IN ('PN', 'CD')
AND owner ='PNET_USER'
AND data_type IN('VARCHAR2', 'CLOB'););
begin
for t in s LOOP
begin
EXECUTE IMMEDIATE 'SELECT count(*) FROM '||t.owner || '.' || t.table_name|| ' WHERE '||t.column_name||' LIKE :1' INTO match_count USING v_like;
IF match_count > 0 THEN
begin
dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
v_sql := 'UPDATE '||t.owner||'.'||t.table_name||' SET '||t.column_name||'= REPLACE('||t.column_name||', '''||v_from||''', '''||v_to||''') WHERE '||t.column_name||' LIKE '''|| v_like||'''';
dbms_output.put_line(v_sql);
EXECUTE IMMEDIATE v_sql;
EXCEPTION WHEN OTHERS THEN
v_emesg := SQLERRM;
dbms_output.put_line(v_emesg);
dbms_output.put_line('Errow while trying to update '||t.owner||'.'||.t.table_name||' : column '||t.column_name||'.';
END;
END IF;
end;
END LOOP;
end;
答案 1 :(得分:-1)
像
这样的东西EXECUTE IMMEDIATE'UPDATE'|| t.table_name ||' SET'|| t.column_name ||'= replace('|| t.column_name ||',''FROM'',''TO'')'
应该这样做,其中FROM是无效字符,TO是您要将其更改为的任何内容。 有关REPLACE如何工作的说明,请参阅链接中的oracle文档。
http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions134.htm
NB我没有任何地方可以尝试这个,所以语法可能不正确。