我在这里有一些代码在IPv4机器上运行良好,但在我们的构建服务器(IPv6)上它失败了。简而言之:
IPHostEntry ipHostEntry = Dns.GetHostEntry(string.Empty);
GetHostEntry的文档说传入string.Empty将获取localhost的IPv4地址。这就是我要的。问题是它在我们的IPv6机器上返回字符串“:: 1:”,我认为这是IPv6地址。
从任何其他IPv4计算机ping机器会提供良好的IPv4地址...并且从其自身执行“ping -4 machinename”会提供正确的IPv4地址....但是经常ping它从它本身给出“:: 1:”。
如何从本身获取此机器的IPv4?
答案 0 :(得分:63)
您是否在回复中查看了all the addresses,丢弃了family InterNetworkV6的那些并仅保留了IPv4的那些?
答案 1 :(得分:43)
查找所有本地IPv4地址:
IPAddress[] ipv4Addresses = Array.FindAll(
Dns.GetHostEntry(string.Empty).AddressList,
a => a.AddressFamily == AddressFamily.InterNetwork);
或使用Array.Find
或Array.FindLast
,如果您只想要一个。
答案 2 :(得分:9)
IPHostEntry ipHostInfo = Dns.GetHostEntry(serverName);
IPAddress ipAddress = ipHostInfo.AddressList
.FirstOrDefault(a => a.AddressFamily == AddressFamily.InterNetwork);
答案 3 :(得分:6)
public Form1()
{
InitializeComponent();
string myHost = System.Net.Dns.GetHostName();
string myIP = null;
for (int i = 0; i <= System.Net.Dns.GetHostEntry(myHost).AddressList.Length - 1; i++)
{
if (System.Net.Dns.GetHostEntry(myHost).AddressList[i].IsIPv6LinkLocal == false)
{
myIP = System.Net.Dns.GetHostEntry(myHost).AddressList[i].ToString();
}
}
}
在公共变量中声明myIP和myHost 并用于表格的任何功能。
答案 4 :(得分:2)
public static string GetIPAddress(string hostname)
{
IPHostEntry host;
host = Dns.GetHostEntry(hostname);
foreach (IPAddress ip in host.AddressList)
{
if (ip.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
//System.Diagnostics.Debug.WriteLine("LocalIPadress: " + ip);
return ip.ToString();
}
}
return string.Empty;
}
答案 5 :(得分:0)
要找到所有有效的地址列表,这是我使用的代码
public static IEnumerable<string> GetAddresses()
{
var host = Dns.GetHostEntry(Dns.GetHostName());
return (from ip in host.AddressList where ip.AddressFamily == AddressFamily.lo select ip.ToString()).ToList();
}
答案 6 :(得分:-3)
的IPv6
lblIP.Text = System.Net.Dns.GetHostEntry(System.Net.Dns.GetHostName).AddressList(0).ToString()
的IPv4
lblIP.Text = System.Net.Dns.GetHostEntry(System.Net.Dns.GetHostName).AddressList(1).ToString()