网站 - 根据鼠标位置更改图像(2个区域)

时间:2012-05-16 09:38:04

标签: javascript html css

我有以下情况非常简单(1页,3个区:左 - 中 - 右):

HTML:

<div class="page">
    <div class="answer-on-the-right-or-left">
        Left zone
    </div>

    <div class="picture-in-the-middle">
        <img src="@Url.Content("/content/images/qres/faceblackandwhite.png")"/>
    </div>

    <div class="answer-on-the-right-or-left">
        Right zone
    </div>
</div>

CSS:

.page { width: 800px; height: 500px; }

.answer-on-the-right-or-left { float: left; width : 300px; height: 500px; }

.picture-in-the-middle { float: left; width : 150px; height: 500px; }

我想做以下事情:

  • 当鼠标位于左侧区域时,中间的图片会变为:"/content/images/qres/facecolorleft.png"
  • 当鼠标位于右侧区域时:"/content/images/qres/facecolorright.png"
  • 其他地方,图片保持不变:"/content/images/qres/faceblackandwhite.png"

我知道如何使用javascript对图片进行鼠标悬停,但我找不到解决此问题的方法。

提前谢谢!

1 个答案:

答案 0 :(得分:1)

为每个区域分配一个ID:

<div class="answer-on-the-right-or-left" id="leftZone">Left Zone</div>
<div class="answer-on-the-right-or-left" id="rightZone">Right Zone</div>

并绑定悬停

$('.answer-on-the-right-or-left').hover(function() {
   var id = $(this).attr('id');
   var img = $('.picture-in-the-middle img');

   if(id == 'leftZone') img.attr('src', '/content/images/qres/facecolorleft.png');
   else if(id == 'rightZone') img.attr('src', '/content/images/qres/facecolorright.png');

}, function() {
   $('.picture-in-the-middle img').attr('src', '/content/images/qres/faceblackandwhite.png');
});