删除“。”之后的部分字符串。

Question

我正在使用NCBI参考序列登录号，如变量a：

a <- c("NM_020506.1","NM_020519.1","NM_001030297.2","NM_010281.2","NM_011419.3", "NM_053155.2")  

要从biomart包中获取信息，我需要在入藏号后删除.1，.2等。我通常使用以下代码执行此操作：

b <- sub("..*", "", a)

# [1] "" "" "" "" "" ""

但正如您所看到的，这不是此变量的正确方法。任何人都可以帮我这个吗？

Answer 1

你只需要逃离这段时间：

a <- c("NM_020506.1","NM_020519.1","NM_001030297.2","NM_010281.2","NM_011419.3", "NM_053155.2")

gsub("\\..*","",a)
[1] "NM_020506"    "NM_020519"    "NM_001030297" "NM_010281"    "NM_011419"    "NM_053155" 

Answer 2

我们可以假装它们是文件名并删除扩展程序：

tools::file_path_sans_ext(a)
# [1] "NM_020506"    "NM_020519"    "NM_001030297" "NM_010281"    "NM_011419"    "NM_053155"

Answer 3

你可以这样做：

sub("*\\.[0-9]", "", a)

或

library(stringr)
str_sub(a, start=1, end=-3)

Answer 4

如果字符串应为固定长度，则可以使用substr中的base R。但是，我们可以使用.获取regexpr的位置，并在substr

中使用它。

substr(a, 1, regexpr("\\.", a)-1)
#[1] "NM_020506"    "NM_020519"    "NM_001030297" "NM_010281"    "NM_011419"    "NM_053155"