Question

我正在尝试构建一个自定义库，其中包含可通过整个站点使用的功能。在/application/libraries内，我创建了一个新文件CustomFuncts：

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
/**
 * @brief CommonFuncts      
 * This class is used to provide common user functions to the whole application.
 *
 * @version 1.0
 * @date May 2012
 *
 * 
 */
class CommonFuncts extends CI_Controller {

 protected $ci;

/**
 * function constructor
 */
function __construct()
{
    $this->ci =& get_instance();
}
 /**
* @brief checkCookie
* 
* Checks for a previous cookie, and if exists:
* @li Loads user details to CI Session object.
* @li Redirects to the corresponding page.
* 
*/
public function verificaCookie(){
    $this->ci->load->view('index');
}
 }
/* End of file CommonFuncts.php */
/* Location: ./application/libraries/CommonFuncts.php */

在控制器welcome.php中：

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Welcome extends CI_Controller {

/**
 * Index Page for this controller.
 *
 * Maps to the following URL
 *      http://example.com/index.php/welcome
 *  - or -  
 *      http://example.com/index.php/welcome/index
 *  - or -
 * Since this controller is set as the default controller in 
 * config/routes.php, it's displayed at http://example.com/
 *
 * So any other public methods not prefixed with an underscore will
 * map to /index.php/welcome/<method_name>
 * @see http://codeigniter.com/user_guide/general/urls.html
 */
public function index()
{
    $this->load->library('commonFuncts');
    $this->commonFuncts->verificaCookie();  
}
}

/* End of file welcome.php */
/* Location: ./application/controllers/welcome.php */

我收到以下错误消息：

A PHP Error was encountered

Severity: Notice

Message: Undefined property: Welcome::$commonFuncts

Filename: controllers/welcome.php

Line Number: 23

Fatal error: Call to a member function verificaCookie() on a non-object in
/var/www/vhosts/unikodf.com/httpdocs/application/controllers/welcome.php on line 23

我尝试了很多东西，包括在库中扩展CI_Controller并使用$this->load->view' instead of $ this-＆gt; ci-＆gt; load-＆gt; view`但我仍然得到了同样的消息。

Answer 1

如果您的图书馆扩展CI_Controller。这意味着您实际上正在扩展控制器的功能。而是像这样声明你的库：

class CommonFuncts { }

您不需要继承CI_Controller，因为您正在编写库而不是控制器，而库不是MVC模型的一部分。它是单一类，它扩展了框架的功能，修复了一个常见问题或者具有许多控制器使用的功能。

要访问它的方法，请使用：

$this->load->library('CommonFuncts');
$this->commonfuncts->verificaCookie();

如果您想简化用于调用库的名称，请使用：

// The second argument is the optional configuration passed to the library
// The third argument is the name with which you would like to access it
$this->load->library('CommonFuncts', '', 'common');
$this->common->verificaCookie(); //  /\ = configuration
//     /\/\/\ = name

Answer 2

您将controllers与libraries混淆。

自定义库不应扩展CI_Controller。 The documentation outlines how to create your own custom library

其次，您需要先加载库，然后才能访问其方法：

$this->load->library('CommonFuncts');
// The "CommonFuncts" library is now ready to use
$this->commonFuncts->verificaCookie();

Answer 3

以下是一些在CI中创建自定义库的好教程

Creating Libraries

Using CodeIgniter Libraries

CodeIgniter - Form: Creating Menu Library

Building with CodeIgniter: Using Libraries

Creating a simple, extensible CodeIgniter authentication library

Creating your own library in CodeIgniter

Answer 4

这里我要修改一件事（我使用代码点火器2.1.3）：

//echo CI_VERSION;  to get the code igniter version
Plesae use
$this->commonfuncts->verificaCookie(); //f is small here commonfuncts
instead of
$this->commonFuncts->verificaCookie();

Answer 5

您的构造函数不正确。你用过：

$this->ci =& get_instance();  //This is invalid syntax.

将codeIgniter分配给变量并在codeigniter的资源上使用该变量

class exampleClass{
    protected $codeIgniter;

    public function __construct()
    {
        $this->codeIgniter =& get_instance();
        $this->codeIgniter->load->helper('url');
        $this->codeIgniter->config->item('base_url');

    }
}

CodeIgniter自定义库错误：调用非对象上的成员函数

5 个答案: