Question

我的搜索功能

     <?php
    $i=0;
    $column_name = 'title'; // column to search by
    $k =$_GET['k'];
    $terms = explode(" ",$k);
    //connect before calling mysql_real_escape_string
    mysql_connect("localhost","","");
    mysql_select_db("test");
    $query ="SELECT bookid,title,author 
    FROM  books WHERE";
    foreach ($terms as $each){
        $i++;
        $each = '%' . $each . '%'; // add wildcard
        $each = mysql_real_escape_string($each); // prevent sql injection
        if($i==1)
            $query .= " $column_name LIKE '$each' ";
        else
            $query .= " OR $column_name LIKE '$each' ";

    }

    echo 'QUERY: ' . $query;

    $query = mysql_query($query) OR DIE(mysql_error());

//Code below is for using the relationships table assuming you have a column name id that
//references to the relationships table. Also, you should add a index on the column id.

$results = "";

while($row = mysql_fetch_array($query)) {
  $results .= '<li>
                <a href="book-relationships.php?id='.$row['id'].'">'.$row['title'].'  author: '.$row['author'].'</a>
              </li>';
}

$results = '<ul>' . $results . '</ul>';

echo $results;

我需要帮助在搜索时将一个数据库与另一个数据库相关联，此数据库列出了所有已经出现在搜索中的书籍，然后将它们与另一个称为关系的表格进行比较，并打印出与该书籍有关系的书籍的标题搜索。

运行搜索时，这是浏览器中生成的内容

QUERY: SELECT id,title,author FROM books WHERE title LIKE '%jarrads%' Unknown column 'id' in 'field list'

任何帮助都会受到赞赏我100％卡住了

架构

书籍 - bookid，title，author，yearpublished，publisher ..... 关系 - relationshipid，bookOne，bookTwo，relationship，relationshiplikes，relationshipdislikes

bookOne和bookTwo，与bookid有关

Answer 1

您的查询中有错误，因为错误消息指出：

Unknown column 'id' in 'field list'

检查您的表格books以获取有效字段列表。实现此目的的一种方法是运行以下查询：

SHOW CREATE TABLE books;

带外键的php搜索引擎

1 个答案: