Question

可能重复：
python: Dictionaries of dictionaries merge

my_dict= {'a':1, 'b':{'x':8,'y':9}}
other_dict= {'c':17,'b':{'z':10}}
my_dict.update(other_dict)

结果：

{'a': 1, 'c': 17, 'b': {'z': 10}}

但我想要这个：

{'a': 1, 'c': 17, 'b': {'x':8,'y':9,'z': 10}}

我该怎么做？（可能以一种简单的方式？）

Answer 1

import collections # requires Python 2.7 -- see note below if you're using an earlier version
def merge_dict(d1, d2):
    """
    Modifies d1 in-place to contain values from d2.  If any value
    in d1 is a dictionary (or dict-like), *and* the corresponding
    value in d2 is also a dictionary, then merge them in-place.
    """
    for k,v2 in d2.items():
        v1 = d1.get(k) # returns None if v1 has no value for this key
        if ( isinstance(v1, collections.Mapping) and 
             isinstance(v2, collections.Mapping) ):
            merge_dict(v1, v2)
        else:
            d1[k] = v2

如果您没有使用Python 2.7+，请将isinstance(v, collections.Mapping)替换为isinstance(v, dict)（用于严格打字）或hasattr(v, "items")（用于打字）。

请注意，如果某个键存在冲突 - 即，如果d1具有字符串值且d2具有该键的dict值 - 则此实现仅保留d2的值（类似于update ）

Python，合并多级词典

1 个答案: