TouchEvent同时执行if和else部分

时间:2012-05-30 06:38:02

标签: android ontouchevent

在下面的代码中我遇到的问题是在onTouchListener方法中,if和else部分每次都被执行。任何人都知道为什么会这样发生?我的项目的目标是在webview上的任何地方进行触摸事件,底座布局必须出现在另一个触摸上它必须消失。任何人都可以帮忙解决这个问题吗?

提前致谢..

     public class MathiasdockActivity extends Activity {
    /** Called when the activity is first created. */
    RelativeLayout upperdock,parent;
    LinearLayout tocbottom,tocparent;
    boolean flag=true;
    WebView wv;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        parent=(RelativeLayout) findViewById(R.id.rl1);
        upperdock=(RelativeLayout) findViewById(R.id.upperdock);
        tocparent=(LinearLayout) findViewById(R.id.tocparent);
        tocbottom=(LinearLayout) findViewById(R.id.linearLayout3);
        upperdock.setVisibility(RelativeLayout.INVISIBLE);
        tocparent.setVisibility(LinearLayout.INVISIBLE);
        tocbottom.setVisibility(LinearLayout.INVISIBLE);
        wv = (WebView) findViewById(R.id.webView1);  
        wv.loadUrl("file:///android_asset/hotspot/07-03.html");
        wv.getSettings().setJavaScriptEnabled(true);


        wv.setOnTouchListener(new OnTouchListener() {

            public boolean onTouch(View v, MotionEvent event) {

                    if(flag)
                    {
                            Toast toast1 = Toast.makeText(getBaseContext(), Boolean.toString(flag) + "if", 1000);
                            toast1.show();
                            upperdock.bringToFront();
                            tocparent.bringToFront();
                            tocbottom.bringToFront();
                            upperdock.setVisibility(RelativeLayout.VISIBLE);
                            tocparent.setVisibility(LinearLayout.VISIBLE);
                            tocbottom.setVisibility(LinearLayout.VISIBLE);
                            flag=false;
                    }
                    else
                    {
                            Toast toast2 = Toast.makeText(getBaseContext(), Boolean.toString(flag) + "else", 1000);
                            toast2.show();
                            wv.bringToFront();
                            upperdock.setVisibility(RelativeLayout.INVISIBLE);
                            tocparent.setVisibility(LinearLayout.INVISIBLE);
                            tocbottom.setVisibility(LinearLayout.INVISIBLE);
                            flag=true;  

                    }

                    return flag;
            }
        });
    }
   }

3 个答案:

答案 0 :(得分:1)

因为OnTouchListener会不断调用,所以您需要检查用户是否第一次触及MotionEvent.ACTION_DOWN

wv.setOnTouchListener(new OnTouchListener() {

        public boolean onTouch(View v, MotionEvent event) {

        if(event.getAction()== MotionEvent.ACTION_DOWN)
        {
                if(flag)
                {
                   Toast toast1 = Toast.makeText(getBaseContext(), Boolean.toString(flag) + "if", 1000);
                   toast1.show();
                   upperdock.bringToFront();
                   tocparent.bringToFront();
                   tocbottom.bringToFront();
                   upperdock.setVisibility(RelativeLayout.VISIBLE);
                   tocparent.setVisibility(LinearLayout.VISIBLE);
                   tocbottom.setVisibility(LinearLayout.VISIBLE);
                   flag=false;
                }
                else
                {
                   Toast toast2 = Toast.makeText(getBaseContext(), Boolean.toString(flag) + "else", 1000);
                   toast2.show();
                   wv.bringToFront();
                   upperdock.setVisibility(RelativeLayout.INVISIBLE);
                   tocparent.setVisibility(LinearLayout.INVISIBLE);
                   tocbottom.setVisibility(LinearLayout.INVISIBLE);
                   flag=true;
                }
          }
              return flag;
        }
    });

答案 1 :(得分:1)

它们看起来似乎都在同时执行。实际上,它们是分开执行的,但是因为触摸事件被如此快速地触发,看起来它们都是同时执行的。您应该做的是首先检测运动事件的类型,例如MotionEvent.ACTION_MOVE或其他东西。否则,所有运动事件都由您的侦听器代码处理。

当然,在您的代码中调用ifelse的原因是因为您在每个语句中将标志设置为true和false,以便语句的执行交替。 / p>

答案 2 :(得分:1)

触摸事件有很多动作,所以请在if条件下使用它。

1.MotionEvent.ACTION_DOWN
2.MotionEvent.ACTION_MOVE
3.MotionEvent.ACTION_UP
.
.
.
etc

并始终return false;

<强>更新

if(event.getAction()== MotionEvent.ACTION_DOWN)
{
  //when you touch on screen
}
else if(event.getAction()== MotionEvent.ACTION_MOVE)
{
    //when you move your finger on screen
}
else if(event.getAction()== MotionEvent.ACTION_UP)
{
  //when you release your finger from screen
}
相关问题