Question

以下是表myTable中的内容。

+--------+--------+--------+--------+
| value1 | value2 | value3 | value4 |
+--------+--------+--------+--------+
|   9    |   4    |   3    |   3    |
|   1    |   2    |   9    |   3    |
|   1    |   2    |   3    |   4    |
|   1    |   2    |   3    |   4    |
+--------+--------+--------+--------+

我希望输出为

+--------+--------+--------+--------+
| value1 | value2 | value3 | value4 |
+--------+--------+--------+--------+
|   1    |   2    |   3    |   4    |
+--------+--------+--------+--------+

value1=1因为1在该列中是三倍。

value2=2因为该列中有两次。

value3=3因为该列中有3个是三次。

value4=4因为4在该列中是两次，而且是该列中所有公共号码的最大数量。

注意：value4最常见的值为3和4.在输出中我应该得到4，因为4是3,4中的最大值。

我可以在mysql中实现这个吗？

更新1

Table at SQL Fiddle

更新2

我也在这里列出答案，所以不需要继续使用js-fiddle。（根据@ypercube回答）

SELECT
  ( SELECT value1
    FROM myTable
    GROUP BY value1
    ORDER BY COUNT(*) DESC
           , value1 DESC
    LIMIT 1
  ) AS value1,

  ( SELECT value2
    FROM myTable
    GROUP BY value2
    ORDER BY COUNT(*) DESC
           , value2 DESC
    LIMIT 1
  ) AS value2,

  ( SELECT value3
    FROM myTable
    GROUP BY value3
    ORDER BY COUNT(*) DESC
           , value3 DESC
    LIMIT 1
  ) AS value3,

  ( SELECT value4
    FROM myTable
    GROUP BY value4
    ORDER BY COUNT(*) DESC
           , value4 DESC
    LIMIT 1
  ) AS value4
;

Answer 1

SELECT
  ( SELECT value1
    FROM myTable
    GROUP BY value1
    ORDER BY COUNT(*) DESC
           , value1 DESC
    LIMIT 1
  ) AS value1,

  ( SELECT value2
    FROM myTable
    GROUP BY value2
    ORDER BY COUNT(*) DESC
           , value2 DESC
    LIMIT 1
  ) AS value2,
...
  ( SELECT valueN
    FROM myTable
    GROUP BY valueN
    ORDER BY COUNT(*) DESC
           , valueN DESC
    LIMIT 1
  ) AS valueN
;

SQL-Fiddle：test-2

Answer 2

这可能不是存储数据的理想方式您可能需要考虑使用键值对来标准化4列（这意味着每列一行）

（你可以使用UNION来实现你想要的目标）

(select value1, null, null, null from TABLE group by value1 order by count(*) desc, value1 desc limit 1)
union
(select null, value2, null, null from TABLE group by value2 order by count(*) desc, value2 desc limit 1)
union
(select null, null, value3, null from TABLE group by value3 order by count(*) desc, value3 desc limit 1)
union
(select null, null, null, value4 from TABLE group by value4 order by count(*) desc, value4 desc limit 1)

查找每列中最常见的值

更新1

Table at SQL Fiddle

更新2

2 个答案: