Question

insert into OPT (email, campaign_id) values('mom@cox.net',100)
where not exists( select * from OPT where (email ="mom@cox.net" and campaign_id =100)) ;

错误报告：SQL错误：ORA-00933：SQL命令未正确结束   00933. 00000 - “SQL命令未正确结束”   *原因：
  *操作：

如果在Oracle中不存在新行，如何插入新行？

Answer 1

insert into OPT (email, campaign_id) 
select 'mom@cox.net',100
from dual
where not exists(select * 
                 from OPT 
                 where (email ="mom@cox.net" and campaign_id =100));

Answer 2

根据已存在的另一条记录插入内容（在Oracle中）的正确方法是使用MERGE语句。

请注意，此问题已经在SO上得到了解答：

Answer 3

insert into OPT       (email,        campaign_id) 
select 'mom@coxnet' as email, 100 as campaign_id from dual MINUS
select                 email,        campaign_id from OPT;

如果OPT中已存在mom@cox.net / 100的记录，MINUS将从select 'mom@coxnet' as email, 100 as campaign_id from dual记录中减去此记录，并且不会插入任何内容。另一方面，如果没有此类记录，则MINUS不会删除任何内容，并且会插入值mom@coxnet / 100。

正如 p.marino 已经指出的那样，merge可能是更好（更正确）的解决方案，因为它专门用于解决您的任务。

Answer 4

MERGE INTO OPT
USING
    (SELECT 1 "one" FROM dual) 
ON
    (OPT.email= 'mom@cox.net' and OPT.campaign_id= 100) 
WHEN NOT matched THEN
INSERT (email, campaign_id)
VALUES ('mom@cox.net',100) 
;

Answer 5

另一种方法是利用oracle的INSERT ALL语法，

INSERT ALL 
    INTO table1(email, campaign_id) VALUES (email, campaign_id)
WITH source_data AS
 (SELECT 'mom@cox.net' email,100 campaign_id
  FROM   dual
  UNION ALL
  SELECT 'dad@cox.com' email,200 campaign_id
  FROM   dual)      
SELECT email
      ,campaign_id
FROM   source_data src
WHERE  NOT EXISTS (SELECT 1
        FROM   table1 dest
        WHERE  src.email = dest.email
        AND    src.campaign_id = dest.campaign_id);

INSERT ALL 还允许我们基于作为源的子查询对多个表执行条件插入。

这里有一些非常干净和不错的示例可供参考。

oracletutorial.com

oracle-base.com/

Oracle插入if not exists语句

5 个答案: