Question

我有以下查询：

Table zone: zone_id, country_id, city_id

SELECT zone.zone_id, city_name
FROM zone
INNER JOIN city
ON city.city_id = zone.city_id
WHERE country_id = 3

结果：

zone_id | city_id
----------------------
17      | New York
16      | Los Angeles

和其他查询：

Table zone , Table management relation: zone_id

SELECT COUNT(user_id)
FROM management
WHERE zone_id = 17

SELECT COUNT(user_id)
FROM management
WHERE zone_id = 16

结果

first query: Count             second query:  Count
             -------                          --------
             5                                2

如何将count（）连接到第一个查询结果的每一行？以这种方式：

zone_id | city_id      | users
--------------------------------
17      | New York     | 5
16      | Los Angeles  | 2

我试过了：

SELECT zone.zone_id, vNombre, COUNT(user_id) AS users
FROM zone
INNER JOIN city
ON city.city_id = zone.city_id
INNER JOIN management
ON management.zone_id = zone.zone_id
WHERE country_id = 3
GROUP BY user_id

但我发现了这个：

zone_id | city_id      | users
--------------------------------
17      | New York     | 5
17      | New York     | 2

Answer 1

SELECT   zone_id, city_name, COUNT(user_id) AS users
FROM     zone
  INNER JOIN city       USING (city_id)
   LEFT JOIN management USING (zone_id)
WHERE    country_id = 3
GROUP BY zone_id, city_name

Mysql：在列中计数（带连接）

1 个答案: